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Damm [24]
3 years ago
15

What is the difference between 6z and z⁶?

Mathematics
1 answer:
Gekata [30.6K]3 years ago
3 0

Answer:

The difference between 6z and z^6 is that 6z is multiplying 6 and z while z^6 is z times z times z times z times z times z

Step-by-step explanation:

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63% of what number is 252
storchak [24]

Answer:

We have, 63% × x = 252

or,

63/100 × x = 252

Multiplying both sides by 100 and dividing both sides by 63,

we have

x = 252 \times  \frac{100}{63 }

x = 400

<h3><u>PLEASE</u><u> MARK</u><u> ME</u><u> BRAINLIEST</u></h3>
7 0
3 years ago
What is the following equation for this graph?
natta225 [31]

Answer: The equation for the graph is x = -4.

6 0
3 years ago
The change from a gift purchase was 3.90.each of 6 students donated an equal amount for the gift.how much change should each stu
rosijanka [135]
Divide 3.90 by 6: 3.9/6=.65. They each paid 65¢ :)
6 0
3 years ago
18% of what number is 99
Artemon [7]
17.82 because you just take the 18% of 99 which is 0.18
4 0
4 years ago
Fertilizer is sold in 100 pound bags labelled with the amount of nitrogen ( N), phosphoric acid ( P2O5), and potash ( K2O) prese
Grace [21]

Answer:

For Vigoro are needed

2929*35.8479 ≅ 104,988.49 (N)

33*3.4351≅113.35 (A)

44*31.2181≅1373.59 (P)

For Parkera are needed

1818*35.8479≅65,171.48 (N)

2525*3.4351≅8673.62 (A)

66*31.2181≅2060.39 (P)

Step-by-step explanation:

we have that in every 100100 pounds of compound nitrogen (N), phosphoric acid (A) and potash (P) are present and that according to the product brand the concentrations vary, therefore:

For Vigoro

2929 N, 33 A, 44 P

For Parkeras

1818 N, 2525 A, 66 P

Now, we need 170170 N, 8787 A and 3434 P of final product containing the components of the types of fertilizers

You can see that the compounds are the same what changes are the proportions from there that

2929N+1818N=170170 ⇒ 4747N=170170 ⇒ N=170170/4747 ≅ 35.8479

33A+2525A=8787 ⇒ 2558A=8787 ⇒ A=8787/2558  ≅ 3.4351

44P+66P = 3434 ⇒ 110P=3434 ⇒ P=3434/110 ≅ 31.2181

Finally

For Vigoro are needed

2929*35.8479 ≅ 104,988.49 (N)

33*3.4351≅113.35 (A)

44*31.2181≅1373.59 (P)

For Parkera are needed

1818*35.8479≅65,171.48 (N)

2525*3.4351≅8673.62 (A)

66*31.2181≅2060.39 (P)

Note: to verify the data, just replace the values ​​in the equations

6 0
3 years ago
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