Question

Algebra 2 - function help!! please help asap!

Answer 1

For functions, even means f(-x)=f(x) and odd means f(-x)=-f(x)

$\sqrt{x^2} - 9$

The only occurrence of x is squared so this is even.

$|x-3|$

This isn't even or odd, it's neither.  f(1)=|1-3|=2.  f(-1)=|-1-3|=4 for example.

$f(x) = \dfrac{x}{x^2-1}$

This one is odd because

$f(-x) = \dfrac{-x}{(-x)^2-1} = -\dfrac{x}{x^2-1} = -f(x)$

$g(x)=x+x^2$

g(1)=1+1=2

g(-1)=-1+1=0

neither odd nor even