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tatuchka [14]
1 year ago
14

The graph of f(x) = (0.5) is replaced by the graph of g(x) = (0.5)x - k. If g(x) is obtained by shifting f(x) down by 3 units, t

hen what is the value of k? A. k=-3 B. k=- 1/3 C. k=1/3 D. k= 3
Mathematics
1 answer:
cricket20 [7]1 year ago
5 0

Recall that the the vertical shifting of functions is associated with the numerical value that is added to the original one. A possitive value k will shift the function k units up, and a negativa value (or subtracting k) will move it vertically down k units.

If I understand correctly, you forgot to type an "x"in the original function f(x), which should read:

f(x) = 0.5 x

Correct?

The new graph is g(x) = 0.5 x - k which is obtained by shifting the original f(x) DOWN by 3 units.

In order to shift the graph of f(x) DOWN three units, we need to SUBTRACT 3 from f(x), leading to : 0.5 x - 3

Therefore, the value of "k"in the given g(x) = 0.5 x - k must be 3.

which agrees with the last option in your list (option D)

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Graph the function f(x) = x3 – 5x2 + 6x using the graphing calculator. What are the solutions to the related equation? Check all
Juli2301 [7.4K]

the solutions to the related equation are 0,2,3 .

<u>Step-by-step explanation:</u>

Here we have , function  f(x) = x3 – 5x2 + 6x . Graph of this function is given below  . We need to find What are the solutions to the related equation . Let's find out:

Solution of graph means the  value of x at which the value of f(x) or function is zero . We can determine this by seeing the graph as at what value of x does the graph intersect or cut x-axis !

At x = 0 .

From the graph , at x=0 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 0^3- 5(0)^2 + 6(0)

⇒ f(0) =0

At x = 2 .

From the graph , at x=2 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 2^3- 5(2)^2 + 6(2)

⇒ f(0) =0

At x=3 .

From the graph , at x=3 we have f(x) = 0 i.e.

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Answer:

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Step-by-step explanation:

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