Explanation: First try the origin (0,0) to rule out two of the graphs. 3y ≥ x - 9 3(0) ≥ (0) - 9 3 ≥ - 9 yes 3x + y > - 3 3(0) + (0) > - 3 3 > - 3 yes so the origin should be in the shaded area of the graph, which rules out the top right and bottom left graphs. Now try a coordinate that is in the shaded area of one of the remaining graphs, but not in the other one. If it works, the graph is the one that has that point in the shaded region, and vice versa. Try point (4, 2) 3y ≥ x - 9 3(2) ≥ (4) - 9 6 ≥ - 5 yes 3x + y > - 3 3(4) + (2) > - 3 12 + 2 > - 3 14 > - 3 yes So the graph is the bottom right one since (4, 2) is included in that shaded region.