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rewona [7]
3 years ago
8

Find the area of the figure.

Mathematics
2 answers:
bazaltina [42]3 years ago
4 0

16 is the answer add all side door

azamat3 years ago
3 0

Answer:

23.5 in²

Step-by-step explanation:

You can find the area of the figure as difference between the area of the right triangle with legs 5+4=9 in and 5+2=7 inches and the area of rectangle with sides 2 inches and 4 inches.

The area of triangle is

A₁=1/2·9·7=31.5 in²

The area of rectangle is

A₂=2·4=8 in²

The area of the figure is

A=A₁-A₂=31.5-8=23.5 in²

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A binary operation is defined on the set of real numbers ℝ by
zloy xaker [14]

Answer:

I. m = 2401

II. ((n+1) ∆ y)/n = 1/n[(n – y + 2)(n – y) + 1]

Step-by-step explanation:

I. Determination of m

x ∆ y = x² − 2xy + y²

2 ∆ − 5 = √m

2² − 2(2 × –5) + (–5)² = √m

4 – 2(–10) + 25 = √m

4 + 20 + 25 = √m

49 = √m

Take the square of both side

49² = m

2401 = m

m = 2401

II. Simplify ((n+1) ∆ y)/n

We'll begin by obtaining (n+1) ∆ y. This can be obtained as follow:

x ∆ y = x² − 2xy + y²

(n+1) ∆ y = (n+1)² – 2(n+1)y + y²

(n+1) ∆ y = n² + 2n + 1 – 2ny – 2y + y²

(n+1) ∆ y = n² + 2n – 2ny – 2y + y² + 1

(n+1) ∆ y = n² – 2ny + y² + 2n – 2y + 1

(n+1) ∆ y = n² – ny – ny + y² + 2n – 2y + 1

(n+1) ∆ y = n(n – y) – y(n – y) + 2(n – y) + 1

(n+1) ∆ y = (n – y + 2)(n – y) + 1

((n+1) ∆ y)/n = [(n – y + 2)(n – y) + 1] / n

((n+1) ∆ y)/n = 1/n[(n – y + 2)(n – y) + 1]

7 0
3 years ago
Consider the sequence defined recursively by do = 0, an = an-1 + 3n – 1. a) Write out the first 5 terms of this sequence,
creativ13 [48]

Answer:

The first 5 terms of the sequence is 2,7,15,26,40.

Step-by-step explanation:

Given : Consider the sequence defined recursively by a_0=0 a_n=a_{n-1}+3n-1

To find : Write out the first 5 terms of this sequence ?

Solution :

a_n=a_{n-1}+3n-1 and a_0=0

The first five terms in the sequence is at n=1,2,3,4,5

For n=1,

a_1=a_{1-1}+3(1)-1

a_1=a_{0}+3-1

a_1=0+2

a_1=2

For n=2,

a_2=a_{2-1}+3(2)-1

a_2=a_{1}+6-1

a_2=2+5

a_2=7

For n=3,

a_3=a_{3-1}+3(3)-1

a_3=a_{2}+9-1

a_3=7+8

a_3=15

For n=4,

a_4=a_{4-1}+3(4)-1

a_4=a_{3}+12-1

a_4=15+11

a_4=26

For n=5,

a_5=a_{5-1}+3(5)-1

a_5=a_{4}+15-1

a_5=26+14

a_5=40

The first 5 terms of the sequence is 2,7,15,26,40.

5 0
3 years ago
I only need #8, but if you want to do the others you can.
lutik1710 [3]
Ralphs is 7.5x+10
frank’s is 10x
7 0
3 years ago
Read 2 more answers
Two consecutive odd integers have sum of 44. Find the integers
satela [25.4K]

Answer:

21, and 23

Step-by-step explanation:

divide 44 by 2 to find the integer that spits it up perfectly into two. Then just add 1 to one 22 and minus 1 to the other. Then its 21 and 23.

8 0
3 years ago
Please help for hw with proportions
frutty [35]
If I’m not mistaken G = 3, hope this helps! ;)
6 0
3 years ago
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