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mestny [16]
3 years ago
11

Evaluate the exponential function ƒ(x) = 8x + 1.

Mathematics
1 answer:
ratelena [41]3 years ago
4 0
<h2>Answer:</h2><h3>3</h3><h2>Explanation:</h2>

Okay, to complete this table all we must do is plug in the right numbers. Okay so the function is, f(x)=8^x+1.

We need to plug in the number 1/3. So to make things easier lets convert 1/3 to a decimal. 1÷3=0.33333333

f(x)=8^0.333+1

f(x)=1.998614186+1

f(x)=2.998614186

Now it's not perfect but the correct answer is 3.

Hope this helps please mark brainliest.

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Answer: 7/8

Step-by-step explanation:

\frac{1}{2}+\frac{3}{8}=\frac{4}{8}+\frac{3}{8}=\frac{7}{8}

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A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function =ht−64t16t2. What is the ma
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This is the concept of applications of polynomial equations. Given that the height of the ball is modeled by the function:
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Find the quotient 16)4.88
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7 0
3 years ago
A data set includes 103103 body temperatures of healthy adult humans having a mean of 98.998.9degrees°f and a standard deviation
dangina [55]

Answer:

98.9-2.62\frac{0.65}{\sqrt{103}}=98.73    

98.9+2.62\frac{0.65}{\sqrt{103}}=99.07    

So on this case the 99% confidence interval would be given by (98.73;99.07)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=98.9 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=0.65 represent the sample standard deviation

n=103 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=103-1=102

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,102)".And we see that t_{\alpha/2}=2.62

Now we have everything in order to replace into formula (1):

98.9-2.62\frac{0.65}{\sqrt{103}}=98.73    

98.9+2.62\frac{0.65}{\sqrt{103}}=99.07    

So on this case the 99% confidence interval would be given by (98.73;99.07)    

6 0
3 years ago
Read 2 more answers
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