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3 years ago

15

David drove 232 miles in 4 hours and 319 miles in 5.5 hours. What is the constant rate of change?

1 answer:

QveST [7]3 years ago

4 0

$\bf \begin{array}{ccll}
hours&miles\\
\cline{1-2}
4&232\\
5.5&319
\end{array}~\hspace{10em}
(\stackrel{x_1}{4}~,~\stackrel{y_1}{232})\qquad
(\stackrel{x_2}{5.5}~,~\stackrel{y_2}{319})
\\\\\\
slope =
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{319-232}{5.5-4}\implies \cfrac{87}{1.5}\implies 58\frac{mi}{hrs}\impliedby \textit{rate of change}$

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