Question

HELP!!!

Answer 1

We can define variable as any factor, trait, or condition that can exist to vary or change.

Perimeter of rectangle = 2(l+w)
let l is the length of the garden
and w is the width of the garden = 6 less than the length = l - 6
perimeter = 188 feet
p = 2(l+w)
188 = 2 (l + (l-6))
188 = 2(l + l - 6)
188 = 2(2l-6)
188 = 4l - 12
4l = 188+12
4l = 200
l=50 
w = l - 6 = 50 - 6 = 44
Thus, the dimensions, length is 50 feet and width is 44 feet.

Answer 2

Let L = length. Therefore, by given information the width, W, is equal to L-6. Perimeter = 2*length + 2*width or 2L+2W. Substitute in values we get 188 = 2*L + 2*(L-6) Expand: 188 = 2*L + 2*L - 12 Add 12 to both sides and combine like terms: 200 = 4*L Divide both sides by 4: 50 = L The length if found to be 50 feet. The width is then 50 - 6, or 44 feet. We can confirm that the perimeter is 50+50+44+44 feet, or 188 feet.