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Elena L [17]
3 years ago
12

Three consecutive even numbers who have a sum of 84

Mathematics
1 answer:
Maksim231197 [3]3 years ago
5 0
84/3=28 The 3 consecutive numbers would be 26,28,and 30
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The slope of the line is the dy/dx value every time it appears in the differential equation. By substituting values for x and y in the DE, the slope can be found for the tangent at a point. This is the value of m in y=mx+a. To find a, plug in the tangent point.
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PLEASE HELP ASAP
finlep [7]

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18/100

Step-by-step explanation:

4 0
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HELP ME PLZ!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!​
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Answer:

Step-by-step explanation:

-1 up and -3 down i think

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Find the distance between each pair of points.If necessary round to the nearest tenth
Dovator [93]

Answer:

Step-by-step explanation:

22) J(2,-1); K(2,5)

Distance = √(x₂-x₁)² + (y₂-y₁)²

                = √( 2- 2)² + (5 - [-1] )²

                = √0 + (5  + 1 )²

                =√ ( 6 )²   = 6

25) A(0,3) ; B (0,12)

distance =√(0-0)² + (12 - 3 )²

              =√( 9)²  = 9

28) Q(12,-12) ; T(5,12)

distance = √(5 - 12)² + (12 - [-12] )²

              = √( -7)² + (12 + 12] )²

              = √ 49 + (24)²

              = √ 49 + 576

               = √625

                 =25

                 

                 

                                     

                 

3 0
3 years ago
In 2010, the average duration of long-distance telephone calls originating in one town was 9.4 minutes. A long-distance telephon
Zepler [3.9K]

<u>Answer</u>: No, we do not have sufficient evidence to conclude that the mean call duration, µ, is different from the 2010 mean of 9.4 minutes.

Step-by-step explanation:

As per given , we have

H_0: \mu=9.4\\\\H_a:\mu\neq9.4, since H_0 is two-tailed so , the test is a two tail test.

Since population standard deviation is unknown, so we use t-test.

Critical value (two-tailed) for significance level of 0.01= t_{n-1,\alpha/2}=t_{49, 0.005}\pm2.609228

For n =50 , \overline{x}=8.6 and s= 4.8

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

t=\dfrac{8.6-9.4}{\dfrac{4.8}{\sqrt{50}}}\approx-1.18

Since test statistic value (-1.18) lies in critical interval (-2.609228, 2.609228), it means the null hypothesis is failed to reject.

We do not have sufficient evidence to conclude that the mean call duration, µ, is different from the 2010 mean of 9.4 minutes.

4 0
2 years ago
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