A quadratic has the form ax^2+bx+c
To factor a quadratic you want to find two values, j and k, which satisfy two conditions...
j*k=a*c and j+k=b
In this case ac=-140 and b=4.
The only values possible are j=14 and k=-10
so jk=-140 and j+k=4 which are the conditions we needed to satisfy...
Now you remove the linear, or "b term", from the original equation and replace it with jx and kx... and in this case you will have:
-2h^2-14h+10h+70 now you can factor out the greatest common factor from the first pair of terms and the second pair of terms...
-2h(h+7)+10(h+7) which is equal to
(-2h+10)(h+7) and you can factor the first term again if you wish...
-2(h-5)(h+7)
The first step to solving this is to eliminate the opposites.
-5 × (-5) - ((3 - 4) × 2)
Calculate the difference from the expression in the parenthesis.
-5 × (-5) - (-1 × 2)
Multiply the numbers on the left side of the expression
25 - (-1 × 2)
Any expression multiplied by -1 equals the opposite,, which will change the expression to the following:
25 - (-2)
When there is a "-" sign in front of the parenthesis,, you must change the sign of each term in the parenthesis. This rule will make the expression look like the following:
25 + 2
Finally,, add the numbers together to get your final answer.
27
This means that the correct answer to your expression is 27.
Let me know if you have any further questions
:)
The answer is 6
First, you must put the values in the formula.
Then, you must simplify the exponents.
Next, subtract 64 on both sides.
Finally, eliminate exponents.
Answer:
2598 units²
Step-by-step explanation:
Sum the parts of the parts of the ratio 3 + 5 + 7 = 15 parts
Divide the perimeter by 15
300 ÷ 15 = 20 ← value if 1 part, thus sides of triangle are
3 × 20 = 60
5 × 20 = 100
7 × 20 = 140
Using Hero's formula to calculate the area
A = 
where s is the semi perimeter and a, b , c are the sides of the triangle
s = 300 ÷ 2 = 150
let a = 60, b = 100 and c = 140, then
A = 
= 
= 
≈ 2598 units²
Answer:
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:
(5,−3)
Equation Form:
x = 5,y = −3
