The inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
<h3>How to determine the inverse relation?</h3>
The function is given as
f(x)=1/3x^2-3x+5
Start by rewriting the function in vertex form
f(x) = 1/3(x - 9/2)^2 -7/4
Rewrite the function as
y = 1/3(x - 9/2)^2 -7/4
Swap x and y
x = 1/3(y - 9/2)^2 -7/4
Add 7/4 to both sides
x + 7/4= 1/3(y - 9/2)^2
Multiply by 3
3x + 21/4= (y - 9/2)^2
Take the square roots
y - 9/2 = √(3x + 21/4)
This gives
y = 9/2 + √(3x + 21/4)
Hence, the inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
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Answer:
The answer to your question is: 45° and 225°
Step-by-step explanation:
Getting tan⁻¹ 1 = 45°
Then, the angle we are looking for is 45°, let's check the for quadrangles.
First quadrangle = tan 45 = 1
Second quadrangle = 180° - 45° = 135° tan 135 = -1
Third quadrangle = 180 + 45 = 225° tan 225 = 1
Forth quadrangle = 360 - 45 = 315° tan 315° = -1
Answer:
yes
Step-by-step explanation:
Answer:(7,-3)
Step-by-step explanation:
Step-by-step explanation:
area of circle= πr²
3.14×7×7
153.86 is the required area
