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crimeas [40]
3 years ago
6

Help me with the work

Mathematics
1 answer:
Tpy6a [65]3 years ago
5 0

Answer:

Option B k > 0

Step-by-step explanation:

we know that

Observing the graph

The slope of the line is positive

The y-intercept is negative

we have

3y-2x=k(5x-4)+6\\ \\3y=5kx-4k+6+2x\\ \\3y=[5k+2]x+(6-4k)\\ \\y=\frac{1}{3}[5k+2]x+(2-\frac{4}{3}k)

The slope of the line is equal to

m=\frac{1}{3}[5k+2]

Remember that the slope must be positive

so

5k+2> 0\\ \\k > -\frac{2}{5}

The value of k is greater than -2/5

Analyze the y-intercept

(2-\frac{4}{3}k) < 0\\ \\ 2 < \frac{4}{3}k\\ \\1.5 < k\\ \\k > 1.5

1.5 is greater than zero

so

the solution for k is the interval ------> (1.5,∞)

therefore

must be true

k > 0

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Leviafan [203]

Answer:

a. H0:μ1≥μ2

Ha:μ1<μ2

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a)

As the score for group 1 is lower than group 2,

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18

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ch4aika [34]

Answer:

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Step-by-step explanation:

Look of a pairs of points for each graph

Line 1                                                  Line 2

A(0, 6)     B (5, 1)                                 C (7,3)               D(5, 1)

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y ≥ - x + 6                                          y ≥ x - 4

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