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weqwewe [10]
3 years ago
12

How do I find the value of u ? What are the steps to find the answer anyone knows ? I’ll give you best brainliest

Mathematics
1 answer:
VikaD [51]3 years ago
4 0

Answer:

u=14

5u=70

Step-by-step explanation:

by angle sum property of quadilateral

88+90+112+5u=360

290+5u=360

5u=360-290

5u=70

u=70/5

u=14

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Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id
Thepotemich [5.8K]

\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

Explanation

\frac{1}{a+bi}=c+di

Step 1

multiplicate by the conjugate

\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}

notice that

\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\  \end{gathered}\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

I hope this helsp you

6 0
1 year ago
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The vertices of ABC are A(2, -3), B(-3,-5), and C(4,1). For each translation,
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Step-by-step explanation:

6 0
2 years ago
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step-by-step.

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Step 1: Simplify both sides of the equation.

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Step 2: Subtract 10 from both sides.

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