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Helen [10]
3 years ago
11

The sides of a right triangle measure 6 times the square root of 3, 6 inches, and 12 inches. If an altitude is drawn from the ri

ght angle to the hypotenuse, what is the length of the segment of the hypotenuse adjacent to the shorter leg? What is the length of the alitude?
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
6 0

Length of segment of the hypotenuse adjacent to the shorter leg is 5 inches and the length of the altitude is 3 inches.

Step-by-step explanation:

Step 1: Let the triangle be ΔABC with right angle at B. The altitude drawn from B intersects the hypotenuse AC at D. So 2 new right angled triangles are formed, ΔADB and ΔCDB.

Step 2: According to a theorem in similarity of triangles, when an altitude is drawn from any angle to the hypotenuse of a right triangle, the 2 newly formed triangles are similar to each other as well as to the bigger right triangle. So ΔABC ~ ΔADB ~ ΔCDB.

Step 3: Identify the corresponding sides and form an equation based on proportion. Let the length of the altitude be x. Considering ΔABC and ΔADB, AB/DB = AC/AB

⇒ 6/x = 12/6

⇒ 6/x = 2

⇒ x = 3 inches

Step 4: To find length of the hypotenuse adjacent to the shorter leg (side AB of 6 inches), consider ΔADB.

⇒ AD^{2} + BD^{2} = AB^{2}

⇒AD^{2} =AB^{2} - BD^{2}

⇒AD^{2} =6^{2} -3^{2}

⇒AD^{2} =36 - 9 = 25

⇒AD = \sqrt{25}

⇒AD = 5 inches

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Montano1993 [528]

f'(x)=\dfrac{4x}{1+7x^2}

Integrating gives

f(x)=\displaystyle\int\frac{4x}{1+7x^2}\,\mathrm dx

To compute the integral, substitute u=1+7x^2, so that \frac27\,\mathrm du=4x\,\mathrm dx. Then

f(x)=\displaystyle\frac27\int\frac{\mathrm du}u=\frac27\ln|u|+C

Since u=1+7x^2>0 for all x, we can drop the absolute value, so we end up with

f(x)=\dfrac27\ln(1+7x^2)+C

Given that f(0)=10, we have

10=\dfrac27\ln1+C\implies C=10

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\boxed{f(x)=\dfrac27\ln(1+7x^2)+10}

7 0
3 years ago
A boundary stripe 6 in. wide is painted around a rectangle whose dimensions are 120 ft by 230 ft. Use differentials to approxima
Nimfa-mama [501]

Answer:

350 square feet

Step-by-step explanation:

We are given that

Width of strip=6 in

Dimension of rectangle=20 ft\times 230 ft

We know that

Area  of rectangle ,A=xy

Differentiate

dA=\frac{\partial A}{\partial x}x+\frac{\partial A}{\partial y}y

We have \frac{\partial A}{\partial x}=y=230 ft

\frac{\partial A}{\partial y}=x=120

dx=\frac{12}{12}=1 ft

1 ft=12 in

Because 6 in added in both side of breadth

dy=\frac{12}{12}=1 ft

Because 6 in added on both sides of length of rectangle

Substitute the values

dA=230\times 1+120\times 1=350 ft^2

Hence, the number of square feet of paint in the strip=350 square feet

7 0
4 years ago
Given z=f(x,y),x=x(u,v),y=y(u,v), with x(4,1)=5 and y(4,1)=2, calculate zv(4,1) in terms of some of the values given in the tabl
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z=f(x(u,v),y(u,v))\implies z_v=f_xx_v+f_yy_v

z_v(4,1)=f_x(5)x_v(4,1)+f_y(2)y_v(4,1)

No table = incomplete answer
3 0
3 years ago
Graph each absolute value function. State the domain, range, and y-intercept.
grandymaker [24]

Answer:

i) D: All real numbers

ii) R: y\le5

iii) Y-int: b=2

Step-by-step explanation:

i) The given absolute value function is

y=-|x+3|+5

The domain is all values of x that makes the function defined.

The absolute value function is defined for all values of x.

The domain is all real numbers.

ii) The given function is y=-|x+3|+5

The function has vertex (-3,5).

The function is reflected in the x-axis.

This means the vertex is the maximum point on the graph of the function.

The maximum y-value is 5.

The range is therefore y\le 5 or (-\infty,5]

iii) To find the y-intercept, put x=0 into the function.

y=-|0+3|+5

y=-|3|+5

y=-3+5

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The y-intercept is (0,2) or b=2

See attachment for graph.

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