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2 years ago

a train travels 16 miles in 20 minutes. at this rate how many minutes will it take to travel 12 miles

Mathematics

1 answer:

Lady_Fox [76]2 years ago

6 0

Answer:

9.6 min

Step-by-step explanation:

16/20 = 0.8 mpm

12(0.8) = 9.6 min

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Find the slope of the line that passes through 5,4 and -4,3

dolphi86 [110]

Answer:

1/9

Step-by-step explanation:

4-3/5--4

1/9

7 0

3 years ago

I need not just the answer but the work written out

Mekhanik [1.2K]

Answer:

A(3) = -6 + (3 - 1) (5)

-6 + (2)(5)

-6 + (10)

A(4) = -6 + (4 - 1) (5)

-6 + (3)(5)

-6 + 15

A(10) = -6 + (10 - 1) (5)

-6 + (9)(5)

-6 + 45

6 0

2 years ago

Solve using the square root property.X^2=-12

Alla [95]

Answer:

x = ± 2i $\sqrt{3}$

Step-by-step explanation:

note that $\sqrt{-1}$ = i

x² = - 12 ( take square root of both sides )

x = ± $\sqrt{-12}$ = ± $\sqrt{4(3)(-1)}$ = ± 2i $\sqrt{3}$

5 0

2 years ago

Darwin's best time for running 5000 metres is 16 minutes. He wants to run it in 15 minutes and 30 seconds.

Rudik [331]

Answer:

3 percent

Step-by-step explanation:

convert to seconds

960 seconds to 930 seconds

30 seconds ÷ 960=3 per cent

6 0

2 years ago

Read 2 more answers

given the recursive formula for a geometric sequence find the common ratio the 8th term and the explicit formula.did I set these

lesya [120]

Answer:

Step-by-step explanation:

1)Since we know that recursive formula of the geometric sequence is

$a_{n}=a_{n-1}*r$

so comparing it with the given recursive formula $a_{n}=a_{n-1}*-4$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-2*(-4)^{7} =32768.$

Explicit Formula = $-2*(-4)^{n-1}$

2) Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=-4*(-2)^{7} =512.$

Explicit Formula = $-4*(-2)^{n-1}$

3)Comparing the given recursive formula $a_{n}=a_{n-1}*3$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =3

8th term= $a_{1}*(r)^{n-1}=-1*(3)^{7} =-2187.$

Explicit Formula = $-1*(3)^{n-1}$

4)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=3*(-4)^{7} =-49152.$

Explicit Formula = $3*(-4)^{n-1}$

5)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-4*(-4)^{7} =65536.$

Explicit Formula = $-4*(-4)^{n-1}$

6)Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=3*(-2)^{7} =-384.$

Explicit Formula = $3*(-2)^{n-1}$

7)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=4*(-5)^{7} =-312500.$

Explicit Formula = $4*(-5)^{n-1}$

8)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=2*(-5)^{7} =-156250.$

Explicit Formula = $2*(-5)^{n-1}$

6 0

2 years ago

a train travels 16 miles in 20 minutes. at this rate how many minutes will it take to travel 12 miles​

a train travels 16 miles in 20 minutes. at this rate how many minutes will it take to travel 12 miles