Answer:
36
Step-by-step explanation:
There are 30 red marbles and the ratio of black to yellow is 4/5, so 4/5=orange/green=orange/30.
30 is 6 times 5, so black=6 times 4=24. There are 24 black marbles.
Total of black and yellow=24+30=54.
40% of the marbles are green so 60% are black/yellow. Also 60% is 54 marbles.
60% is 60/100=3/5 so 3/5 of the total is 54 marbles, therefore 1/5 is 54/3=18 and 2/5 is the number of red marbles=2 times 18=36 red marbles.
to be honest i can't think of anything original for the visual thing, but i think the pi chart from the person above me would work well
Supposing 30 days in the month of May (which is not always same in every year),we have,
S= Sample Space
n(S)=total days in a year=365 days
n(E)=no of favourable events
= no of days in the month of May=30 days
Then the probability is of favourable events is,
P(E)=n(E)/n(S)=30/365=6/73
Now,the probability that the birthday is not in May is,
P'(E) =1-6/73=67/73 ANS!!!
Answer:
0
Step-by-step explanation:
Given
- 0.4(3x - 2) + 
← substitute x = 4 into the expression
= - 0.4(3(4) - 2) + 
= - 0.4(12 - 2) + 
= - 0.4(10) + 
= - 4 + 4 = 0
To determine the amount of milk that David should be adding, we need to generate and expression that would relate the number of strawberries and the number of cups. From the problem statement, it is said that the number of strawberries is directly proportional to the number of cups of milk. We write it as:
X α Y where X represents the number of strawberries and Y represents the number of cups of milk
To get rid of the proportionality sign, we introduce a proportionality constant k. We calculate this by using the initial conditions given.
X = kY
at X = 14 strawberries Y = <span>2 1/2 cups of milk = 5/2 cups
14 = k(5/2)
k = 28/5
At X = 203
X = kY
203 = 28/5 (Y)
Y = 145/4 or 36 1/4 cups of milk needed</span>
