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Ratling [72]
3 years ago
12

Which facts are true for the graph of the function below? Check all that apply.f(x)= log0.725 x

Mathematics
1 answer:
Soloha48 [4]3 years ago
5 0

Answer:

C.

The x-intercept is (1, 0).

done

D.

The range is all real numbers.

done

E.

It is decreasing.

done

F.

The domain is x > 0.

Step-by-step explanation:

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In the given figure, what is the measure of angle CPE?
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Answer:

Option B

Step-by-step explanation:

The 2 lines in this circle make a linear pair. this means that ∠CPE and ∠FPD are congruent this also means that their arcs are congruent. so you start out by setting 2x + 28 equal to 4x + 12. after you solve for x you should get x=8, inputting this into the angle equation (x + 60) and you should get 68

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4 years ago
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AURORKA [14]

Answer:

666

Step-by-step explanation:

Because I said so.

5 0
4 years ago
7 ft x 15ft x 17 ft<br> What kind of triangle
victus00 [196]
I think the answer is a scalene triangle
6 0
3 years ago
Read 2 more answers
The publisher of a recently released nonfiction book expects that over the first 20 months after its release, the monthly profit
wolverine [178]

Answer:

(a)\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

(b)P'(5)=-($4.54) Thousand

(c)P'(11)=-($2.10) Thousand

(d)The fifth Month

Step-by-step explanation:

Given the monthly profit model:

P(t)=\frac{240t-40t^2}{t^2+20}

(a)We want to derive a model that gives the Marginal Profit, P' of the book.

We differentiate

P(t)=\frac{240t-40t^2}{t^2+20} using quotient rule.

\frac{dP}{dt}=\frac{(t^2+20)(240-80t)-(240t-40t^2)(2t)}{(t^2+20)^2}

Simplifying

\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

We have derived a model for the marginal profit.

(b) After 5 months, at t=5

Marginal Profit=P'(5)

\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

P^{'}(5)=\frac{4800-1600(5)-240(5)^2}{(5^2+20)^2}

=-($4.54) Thousand of dollars

(c)Marginal Profit 11 Months after book release

P^{'}(11)=\frac{4800-1600(11)-240(11)^2}{(11^2+20)^2}

=-($2.10) Thousand of dollars

(d) Since the marginal profit at t=5 is negative, after the 5th Month, the profit starts to experience a steady decrease.

6 0
3 years ago
I need help on this statistic problem.
vladimir1956 [14]

Answer:

Option B.

Step-by-step explanation:

In a regression of y in x, the proportion oh the variation in y explained by the variable x is shown in the R-squared value. So, for answering this question we need to look at the R-squared of such regression.

In this case the R-squared is 98.9% (or 0.989), so we will the option that matches this value. Looking at your options, the one that matches the R-squared is option B.

So, B is the correct option.

3 0
3 years ago
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