Let's say you want to compute the probability

where

converges in distribution to

, and

follows a normal distribution. The normal approximation (without the continuity correction) basically involves choosing

such that its mean and variance are the same as those for

.
Example: If

is binomially distributed with

and

, then

has mean

and variance

. So you can approximate a probability in terms of

with a probability in terms of

:

where

follows the standard normal distribution.
Answer:
C. 7x + 11
Step-by-step explanation:



Answer: 3/8
Step-by-step explanation: Multiply 3/4 and 1/2, or
, which equals 3/8
Answer:
see explanation
Step-by-step explanation:
Given A = 3x² + 2y + 2 and B = 6x² - 8y + 1 , then
A + B
= 3x² + 2y + 2 + 6x² - 8y + 1 ← collect like terms
= 9x² - 6y + 3
-------------------------------
A - B
= 3x² + 2y + 2 - (6x² - 8y + 1) ← distribute parenthesis by - 1
= 3x² + 2y + 2 - 6x² + 8y - 1 ← collect like terms
= - 3x² + 10y + 1
3 bags are needed to cover the flower bed.