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dalvyx [7]
3 years ago
10

Combine Like Terms. 2 x 2 − x 2 + 3 x 2 2x 2 −x 2 +3x 2

Mathematics
1 answer:
Marta_Voda [28]3 years ago
8 0

Answer:

The answer is 4x(exponent of 2)

Step-by-step explanation:

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Prove the quotient of any two rational numbers is a rational number
Brut [27]
That is not possible, a quotient or any equation for that fact can only be rational when it lacks repeating {x} values. Take for instance this 2x11x2^2+(1+10)=

In the equation the {x} values would be most likely described as {2}. Since 2 was the quotient that was being repeating hence that equation not being rational. Hope this helps!



4 0
3 years ago
Can some one find the area and perimeter?? Please!!!
motikmotik
I can but i need the question lol.
6 0
4 years ago
Help needed! Thank you!
Gelneren [198K]

Answer:

C but see below.

Step-by-step explanation:

If I'm reading this correctly, you mean 31/24. It really can't be much else.  The sine and cosine are both incorrect because both involve the hypotenuse which must be calculated in order for them to be considered. In addition 31/24 is greater than one which is impossible for both the Sine and the Cosine.

That leaves K and D

Tan(D) = 24/31 which is not an option.

That leaves C.

tan(K) = 31/24 which is what you have to choose. If your choice is not written this way, then there is no answer.

3 0
3 years ago
Solve the following equation.
serious [3.7K]

Answer:

x²-10×+25=16

ײ-10×=16-25

×(×-10)=-9

but if your question is rather 2x-10×+25=16

then here goes the answers

2x-10×+25=16

-8×=16-25

-8×=-9

×=9/8

×=1¹/8

4 0
4 years ago
Wile E. Coyote is pursuing the Road Runner across Great Britain toward Scotland. The Road Runner chooses his route randomly, suc
Elina [12.6K]

Answer:

0.444

Step-by-step explanation:

The objective is to draw the tree diagram and find the probability that the roadrunner took the high road, given that he was caught.

The tree diagram is attached in the image below:

The required probability can be computed as:

P(high\  road  \ | \  caught) = \dfrac{P(high  \ road \  and \  caught)} {P(caught)} \\ \\ P(high \  road  \ |  \ caught) = \dfrac{P(high \  road  \ and  \ caught)}{P(high \  road  \ and  \ caught)+P(low  \ road  \ and  \ caught)}

P(high  \ road \  |  \ caught) =\dfrac{ 0.8*0.01 }{ 0.80*0.01 + 0.20*0.05} \\ \\ P(high \ road  \ | \ caught) = \dfrac{0.008 }{ 0.008 + 0.01} \\ \\

P(high \ road  \ | \ caught) = \dfrac{0.008 }{ 0.018}

\mathbf{P(high \ road  \ | \ caught) = 0.444}

8 0
3 years ago
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