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3 years ago

A rectangle measures 1 1/ 2 inches by 3/ 4 inches. What is its area?

1 answer:

4 0

Area equals base x height. 1 1/2 = 1.5 and 3/4 = .75
Multiply those together and you’ll get 1.125 which is your area. You can also write it as 9/8

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Please help! 10 points and brainlyist!!

yarga [219]

Answer:

1.80 in^3

1.0 fluid ounces^3

Step-by-step explanation:

volume of a cone = 1/3 πr²h

π = 3.14

r = 2.2 / 2 = 1.1

h = the value of h can be determined using Pythagoras theorem

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

c = hypotenuse

1.8² = 1.1² + b²

3.24 = 1.21 + b²

3.24 - 1.21 = b²

2.03

b = √2.03 = 1.42

Volume = 1/3 x 3.14 x 1.21 x 1.42 = 1.80 in^3

1.80 x 0.554 = 1.0 fluid ounces^3

5 0

3 years ago

Please help will offer brainliest

Nutka1998 [239]

Answer: witch one?

Step-by-step explanation:

3 0

3 years ago

The total weight of a rock depends on its size and is proportional to its density. In this context, density is the weight per cu

kow [346]

Answer:

$d = \frac{w}{48}$

If $\frac{1}{48} \\$ is constant, say k

Then,

$d = kw$

∴ d ∝ w

Hence, weight is proportional to the density

Step-by-step explanation:

From the question,

Let w denote the weight of the rock in pounds

s denote the size of the rock in cubic inches and

d denote the density of the rock in pounds per cubic inch.

First, we will write the equation connecting w, s, and d.

We get

$density (pounds/inch^{3} ) = \frac{weight(pounds)}{size (inch^{3}) }$

That is,

$d = \frac{w}{s}$

Now, given a 48-cubic-inch rock with weight w pounds, to show the proportional relation between the weight and the density, we will write

$d = \frac{w}{48}$

If $\frac{1}{48} \\$ is constant, say k

Then,

$d = kw$

∴ d ∝ w

Hence, density is proportional to the weight OR weight is proportional to the density

4 0

3 years ago

Match each statement to it’s corresponding reason. Drake the items on the left to the correct location on the right PLEASE AND T

andreyandreev [35.5K]

Answer:

Step-by-step explanation:

1) $\angle AED$ and $\angle BEC$ are vertical angles

2) $\angle AED$ and $\angle BEC$ are created by intersecting lines (definition of vertical angles)

3) $\angle AED$ and $\angle AEB$ form a linear pair, $\angle AEB$ and $\angle BEC$ form a linear pair

4) $\angle AED$ and $\angle AEB$ are supplementary, $\angle AEB$ and $\angle BEC$ are supplementary

5) $\angle AED \cong \angle BEC$

6 0

2 years ago

Find the equation of the axis of symmetry of the following parabola algebraically.<br> y=2x^2+16.

Inessa05 [86]

Answer:

x = 0

axis of symmbery = -b/2a or x vertex on quadratic equation

0/4=0

x=0

Step-by-step explanation:

3 0

3 years ago