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2 years ago

What is the equation of the line written in general form? Y-intercept of 5, x-intercept of 5

Mathematics

1 answer:

SVEN [57.7K]2 years ago

6 0

I think the answer is y=5x+5

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X-3 divided by 4 = 12

yulyashka [42]

Answer:

x = 51

Step-by-step explanation:

(x-3) /4 = 12

Multiply each side by 4

(x-3) /4 *4 = 12*4

x-3 = 48

Add 3 to each side

x-3+3 = 48+3

x = 51

4 0

3 years ago

Read 2 more answers

Mrs. lama marked a price of a cosmetic item 25% above it's cost price. if the cost price of the cosmetic item was 4400, at what

Alexeev081 [22]

Answer:

hi dear I suppose the answer would be 6271$

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2 years ago

Aproximati prin lipsa si prin adaos la mii numerele:

siniylev [52]

Do you talk romanian. and i think that it is g.

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2 years ago

Find the first term and the common ratio <br>third term =6 and seventh term= 96

mamaluj [8]

Answer:

First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: $a_n= a_1r^{n-1}$

We are given: third term = 6 i,e

$a_3=a_1r(3-1)\\6=a_1r^2----eq(1)$

Seventh term = 96

$a_7=a_1r(7-1)\\96=a_1r^6----eq(2)$

Dividing eq(2) and eq(3)

$\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}$

So, Common Ratio r = 2

Finding First term using eq(1)

$a_3=a_1r^2\\6=a_1(2)^2\\6=a_1(4)\\a_1= \frac{6}{4}\\a_1= \frac{3}{2}$

So, First term a₁ = 3/2 and common ratio r = 2

6 0

2 years ago

The area and length of a rectangle are given. What is the width?

mars1129 [50]

I can’t really tell uu the answer but I think it’s 5 length long

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3 years ago