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a_sh-v [17]
3 years ago
10

PLEASE PLEASE HELP I'LL GIVE YOU BRAINIEST ANSWER!!!!!!this is quotient rule btw (calculus)​

Mathematics
2 answers:
MariettaO [177]3 years ago
8 0

Answer:

(C) -6 is the correct option.

please thanks❤ me and follow me

Basile [38]3 years ago
8 0
C -6 is the correct answer
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PLEASE HELP IM SO STUCK 20 POINTS
prohojiy [21]

Answer: X = 2

Step-by-step explanation: The correct answer to this question is that x=2. Regardless of what point you go to on the line, it always has a value of 2 because it is going vertically (up and down) at 2.

5 0
3 years ago
Whats -6-10k if k=-1​
defon

Answer:

The answer would be 4

Step-by-step explanation:

Calculate it

3 0
2 years ago
Read 2 more answers
prove that sin theta cos theta = cot theta is not a trigonometric identity by producing a counterexample
Zolol [24]

Answer:

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Begin with the right hand side:

R.H.S = cot θ = \frac{cos \ \theta}{sin \ \theta}

L.H.S = sin θ cos θ

so, sin θ cos θ ≠ \frac{cos \ \theta}{sin \ \theta}

So, the equation is not a trigonometric identity.

=========================================================

<u>Anther solution:</u>

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Assume θ with a value and substitute with it.

Let θ = 45°

So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2

R.H.S = cot θ = cot 45 = 1

So, L.H.S ≠ R.H.S

So, sin θ cos θ = cot θ is not a trigonometric identity.

5 0
2 years ago
100 POINTS! IF YOU ANSWER THESE 5 QUESTIONS CORRECTLY :)
Sergeeva-Olga [200]

1. Use a computer to randomly select 30 student IDs from all her students2. If the ice cream store owner asks 2300 people, will most likely pick cheesecake to be the flavor of the month.3. I would need the line plot4. I would need the graph to solve5. I would need the graph to solveClick to let others know, how helpful is it


Read more on Brainly.com - brainly.com/question/3239357#readmore

5 0
3 years ago
Read 2 more answers
What is the equation of a line passing through (5,2) and parallel to the line represented by the equation y - 2x + 1?
34kurt

Step-by-step explanation:

Im not sure if its supposed y = -2x + 1 or y = 2x + 1 but I'll solve the problem for both.

First for y = -2x + 1

Since the line has to be parallel to y = -2x + 1

the slopes would be the same.

so, so far the equation would be

y = -2x + b

now we substitute (5,2) into the equation

2 = -2(5) + b

2 = -10 + b (Add 10 to both sides of the equation)

+10 +10

12 = b

Now that we solved for b

The equation would be

y = -2x + 12

^^ This equation is parallel to y = -2x + 1

Now to solve for an equation parallel to y = 2x + 1

Both equations would have the same slope

So far we would have

y = 2x + b

Now we solve for be by substituting the point (5,2)

2 = 2(5) + b

2 = 10 + b (subtract 10 from both sides)

-10 -10

-8 = b

After solving for b

The equation is

y = 2x - 8

This equation is parallel to y = 2x + 1

4 0
3 years ago
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