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4 years ago

Find the value of x.

Mathematics

1 answer:

viktelen [127]4 years ago

6 0

A is the closest, hope this helped

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An equilateral triangle has a semiperimeter of 6 meters. What is the area of the triangle? Round to the nearest square meter. 2

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3 years ago

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Please help with three questions!! Worth 98 points!!

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Please show us the questions and will help further this discussion.

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Which equation shows the quadratic formula used correctly to solve 5x2 + 3x – 4 = 0 for x? x = StartFraction negative 3 plus-or-

Brrunno [24]

Answer: FIRST OPTION

Step-by-step explanation:

<h3> The missing picture is attached.</h3>

By definition, given a Quadratic equation in the form:

$ax^2+bx+c=0$

Where "a", "b" and "c" are numerical coefficients and "x" is the unknown variable, you caN use the Quadratic Formula to solve it.

The Quadratic Formula is the following:

$x=\frac{-b \±\sqrt{b^2-4ac} }{2a}$

In this case, the exercise gives you this Quadratic equation:

$5x^2 + 3x - 4 = 0$

You can identify that the numerical coefficients are:

$a=5\\\\b=3\\\\c= - 4$

Therefore, you can substitute values into the Quadratic formula shown above:

$x=\frac{-b \±\sqrt{b^2-4ac} }{2a}\\\\x=\frac{-3 \±\sqrt{(3)^2-4(5)(-4)} }{2(5)}$

You can identify that the equation that shows the Quadratic formula used correctly to solve the Quadratic equation given in the exercise for "x", is the one shown in the First option.

6 0

4 years ago

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The triangles below are similar. Find x showing the proportion and all work.

zavuch27 [327]

we are given that

two triangles are similar

so, the ratio of their sides must be same

we get

$\frac{2}{6} =\frac{x}{x+2}$

now, we can solve for x

step-1: Cross multiply both sides

$2(x+2) =6x$

step-2: Simplify left side

$2x +4 =6x$

step-3: Subtract both sides by 2x

$2x +4-2x =6x-2x$

$4 =4x$

step-4: Divide both sides by 4

$x=1$

so,

$x=1$ ............Answer

7 0

4 years ago

6.1.3 quiz pythagorean theorem question 9

Olegator [25]

Answer: 14.73

Step-by-step explanation:

The given triangle is a right angle triangle.

EF^2 + DF^2 = ED^2

The hypotenuse is |ED| while the two shorter legs are |EF| and |DF|.

We can then apply the Pythagoras Theorem to find the length of EF.

(EF)^2 + (DF)^2 = (ED)^2

(EF)^2 + (12)^2 = (19)^2

(EF)^2 + 144 = 361

(EF)^2 = 361 - 144

(EF)^2 = 217

EF = 14.73

6 0

3 years ago