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4vir4ik [10]
1 year ago
6

If x-2 divides p(x) evenly, which statement must be true?

Mathematics
1 answer:
tankabanditka [31]1 year ago
3 0

If x - 2 divides p(x) evenly, the statement that is correct is; p(2) = 0

<h3>How to carry out division of quadratic functions?</h3>

We know that a factor of a polynomial completely divides that polynomial without any remainder.

For example, we want to divide the polynomial x² - 2x - 8 by (x + 2). This means that for it to be completely divisible, then f(-2) must be equal to zero. Thus, let us check it;

f(-2) = (-2)² - 2(-2) - 8

f(-2) = 4 + 4 - 8

f(-2) = 0

Now, we are told that x - 2 divides p(x) evenly. Thus, this means that;

p(2) = 0

Read more about Division of quadratic functions at; brainly.com/question/17057112

#SPJ1

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Answer:

4

Step-by-step explanation:

log(50×50)×log(2×2)

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log(2500×4)

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4 0
3 years ago
Which of the following
Archy [21]

The answer you are looking for is 36.

If you line up the numbers numerically (4, 8, 16, 32, 36, 64), you'll see that there's a pattern. Each number, multiplied by 2, gets the next number in the sequence. 4 * 2 = 8, 8 * 2 = 16, 16 * 2 = 32, and 32 * 2 = 64.

Thus meaning 36 is the odd number out. I hope this helps!

6 0
4 years ago
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3 years ago
1+2000000000000000000000000000000000000
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7 0
3 years ago
Explorers on a planet with a thin atmosphere want to measure the acceleration of gravity at its surface. So they use a spring gu
Murljashka [212]

Answer:

The value of g_s is g_s=\frac{30}{21} \:\frac{m}{s^2}.

Step-by-step explanation:

We know that the position function is given by

s(t)=30t-\frac{g_s}{2} t^2

Velocity is defined as the rate of change of position. Therefore,

v(t)=\frac{d}{dt}(s(t))

So, the velocity function is

v(t)=\frac{d}{dt}(s(t))\\\\v(t)=\frac{d}{dt}(30t-\frac{g_s}{2} t^2)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(30t\right)-\frac{d}{dt}\left(\frac{g_s}{2}t^2\right)\\\\v(t)=30-g_st

When a body reaches a vertical velocity of zero, this is the maximum height of the body and then gravity will take over and accelerate the object downward. Thus,

v(t)=30-g_st=0\\\\g_s=\frac{30}{t}

We know that the ball bearing reaches its maximum height 21 seconds after being launched (t = 21 s).

So, the value of g_s is g_s=\frac{30}{21} \:\frac{m}{s^2}.

5 0
4 years ago
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