180 ≥ 45 + 15x
<u> -45</u> <u>-45 </u>
135 ≥ 15x
9 ≥ x
x ≤ 9
Answer: D
66 < 2x + 28
<u>-28 </u> <u> -28 </u>
38 < 2x
19 < x
x > 19
Answer: C <em>the answer could also be B</em>
11 < 5 + 2x
<u>-5</u> <u>-5 </u>
6 < 2x
3 < x
x > 3
Answer: E <em>the answer could also be A, B, and C</em>
-30 ≥ 6 - 4x
<u> -6</u> <u> -6 </u>
-36 ≥ -4x
9 ≤ x
x ≥ 9
Answer: A
- 4 ≥ 5
<u> + 4 </u> <u>+ 4 </u>
≥ 9
12 ≥ 12(9)
x ≥ 108
Answer: B
For the given function f(t) = (2t + 1) using definition of Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].
As given in the question,
Given function is equal to :
f(t) = 2t + 1
Simplify the given function using definition of Laplace transform we have,
L(f(t))s =
=
=
= 2 L(t) + L(1)
L(1) =
= (-1/s) ( 0 -1 )
= 1/s , ( s > 0)
2L ( t ) =
=
= 2/ s²
Now ,
L(f(t))s = 2 L(t) + L(1)
= 2/ s² + 1/s
Therefore, the solution of the given function using Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].
Learn more about Laplace transform here
#SPJ4