I think the answer would be (A.)
let x be the first integer
x+ 2 the second integer ( two consecutive even )
smaller integer added to three times the larger <span>x + 3 ( x+2)
</span>two less than five times the smaller <span>5x - 2</span>
x + 3 ( x+2) = 5x - 2
x+3x +6 = 5x -2
x=8
the first integer = 8
the second is x+2 =10
Add them all up to get it
B. ) Unless you're missing some data.
Step-by-step explanation:
Alternate and corresponding angles.
