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scoundrel [369]
3 years ago
6

A circle with radius 9 has a sector with a central angle of 120°.

Mathematics
1 answer:
Vitek1552 [10]3 years ago
8 0

120º is 1/3 of a complete revolution of 360º. So the area of this sector should be 1/3 the area of the complete circle.

A circle with radius 9 has area 9^2 π = 81π.

So the sector has area 81π/3.

Put another way: The area <em>A</em> of a circular sector and its central angle <em>θ</em> (in degrees) occur in the same ratio as the area of the entire circle with radius <em>r</em> according to

<em>A</em> / <em>θ </em>º = (π <em>r </em>^2) / 360º

==>  <em>A</em> = π/360 <em>θ r</em> ^2

In this case, <em>r</em> = 9 and <em>θ</em> = 120º, so

<em>A</em> = π/360 * 120 * 81 = 81π/3

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