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oee [108]
3 years ago
5

The area of a rectangle is found by the product of its length and its width. Determine an expression for the area of a rectangle

with a length of 0.36p units and a width of 1.24 units.
1.6 p
0.36 p + 1.24
4.464 p
0.4464 p
(0.36 p) ∙ (1.24)
Mathematics
1 answer:
julia-pushkina [17]3 years ago
3 0

Answer:

The last option (0.36p) (1.24)

Step-by-step explanation:

to determine an area u multiply length times width

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One major reason that the two-sample t procedures are widely used is that they are quite robust. What does this mean? t procedur
Monica [59]

Answer:

Confidence levels and P-values from the t procedures are quite accurate even if the population distribution is not exactly Normal

Step-by-step explanation:

Confidence levels and P-values from the t procedures are quite accurate even if the population distribution is not exactly Normal

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4 0
3 years ago
From 1970 to 1980, the consumer price index (CPI) increased from 38.8 to 82.4. If a dozen eggs cost $0.25 in 1970 and the price
Ganezh [65]
Understanding the Question
This may not be the actual way that the US government prepares the CPI, but it will provide a comparison. 

You can set up a proportion. The base number for the CPI is 38.8 in 1970. That number (38.8) has more than doubled to get to 82.4, which also tells us that there was inflation. What your parents and grandparents bought in 1970 went to double the amount in 1980. Gasoline certainly did that.

Givens
CPI in 1970 = 38.8
CPI in 1980 = 82.4
Eggs 1970 =  0.25
Edgs 1980 = X

Formula substitution and solution
CPI 1970 / CPI 1980 = cost of eggs 1970 / cost of eggs 1980
38.8/82.4 = 0.25 / x Cross multiply
38.8 * x = 0.25 * 82.4
38.8 * x = 20.625
x = 20.628 /38.8
x = 0.53 dollars of 53 cents.

53 cents in 1980 which is slightly double as predicted.

Footnote
As a matter of interest, my wife tells me that eggs now cost about 3.58 where we live. That's almost 7 times as expensive as they were in 1980. Something to think about. By the way, the price quoted is in Canada.
7 0
3 years ago
ms.conner's class is collecting quarters to buy a present for a homeless shelter .last week they collected $15.50 . How many qua
Alenkinab [10]

Answer:

62 quarters

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Which polynomial can be simplified to a difference of squares
Mrrafil [7]
<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)

<h2>Why?</h2>

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

First=10a^{2}

Second=16a^{2}

Third=25a^{2}

Fourth=24a^{2}

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So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

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16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}

7 0
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