Answer:
-2,-6,-18
Step-by-step explanation:
let g1,g2,g3 be three G.M.s between -2/3 and -54
now -2/3,g1,g2,g3,-54 are geometric
n=5
an=a1 r^{n-1}
-54=-2/3 r^{5-1}
r^{4}=-54×-3/2=81=3^4
r=3
g1=a1×r=-2/3×3=-2
g2=a1×r²=-2/3×3²=-6
g3=a1×r³=-2/3×3³=-18
(-2,-4)
Due to the intervals between the points this would be the answer because the pattern shown.
84. 4•2=8 8+4=12. The second digit must be less than 5 to create a single digit answer for your tens place.
Okay... by using long division method first
we have
x²-2x-16 ÷ x+3
quotient = x-5 , remainder = -1
using factor Theorem
we have
f(-3) = (-3)² -2(-3) -16 = 9+6-16 = -1 (remainder)
so the remainder theorem is valid
6w+3(4w-2)= 18w-6
=
16w+ 2(w-3)