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3 years ago

How do I figure out the area and perimeter of these shapes and how do you figure out the unknown side? Q9

Mathematics

1 answer:

nydimaria [60]3 years ago

4 0

To work out the area or perimeter of any compound shape, split the shape so that you are left with regular shapes e.g. for 9b split the shape and you will get two rectangles

Then you can easily work the area/perimeter of the shapes you made and add them up

Hope this helps :)

You might be interested in

Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = e−4x, [0, 2] Yes, it does not m

Zigmanuir [339]

Answer:

(a) Yes, it does not matter if f is continuous or differentiable; every function satisfies the Mean Value Theorem.

(b) $c =0.51995$

Step-by-step explanation:

Given

$f(x) = e^{-4x};\ [0,2]$

Solving (a); Does the function satisfy M.V.T on the given interval

We have:

$f(x) = e^{-4x};\ [0,2]$

The above function is an exponential function, and it is differentiable and continuous everywhere

Solving (b): The value of c

To do this, we use:

$f'(c) = \frac{f(b) - f(a)}{b - a}$

In this case:

$[a,b] = [0,2]$

So, we have:

$f'(c) = \frac{f(2) - f(0)}{2 - 0}$

$f'(c) = \frac{f(2) - f(0)}{2}$

Calculate f(2) and f(0)

$f(x) = e^{-4x}$

So:

$f(2) = e^{-4*2} = e^{-8} = 0.00033546262$

$f(0) = e^{-4*0} = e^{0} = 1$

This gives:

$f'(c) = \frac{0.00033546262 - 1}{2}$

$f'(c) = \frac{-0.99966453738}{2}$

$f'(c) = -0.4998$

Note that:

$f'(x) = (e^{-4x})'$

$f'(x) = -4e^{-4x}$

This implies that:

$f'(c) = -4e^{-4c}$

So, we have:

$f'(c) = -0.4998$

$-4e^{-4c} =-0.4998$

Divide both sides by -4

$e^{-4c} =\frac{-0.4998}{-4}$

$e^{-4c} =0.12495$

Take natural logarithm of both sides

$\ln(e^{-4c}) =\ln(0.12495)$

$\ln(e^{-4c}) =-2.0798$

Apply law of natural logarithm

$\ln(e^{ax}) =ax$

So:

$-4c =-2.0798$

Solve for c

$c =\frac{-2.0798}{-4}$

$c =0.51995$

3 0

3 years ago

Pleaseeeeee I need help! THANK YOU

amm1812

$\: \: \: \: \: \: \:$

$\frac{3}{10} \\ \\ or \: in \: alternate \: \: form \\ \\ 0.3$

<h2>refer to the attachment for explanation</h2>

<h2>hope it helps</h2>

4 0

3 years ago

Read 2 more answers

A class of 165 students went on a field trip. They

navik [9.2K]

answer

the number of buses is 3

the number of cars is 6

Step-by-step explanation:

total number of the students=165

total number of the vehicles=9

let x represent the number of cars

let y represent the number of buses

x+y=9...........equation 1

(the number of the cars plus the number of the buses= to the number of vehicles )

5x + 45y=165.......equation 2

(the number of student the car can hold plus the number of student the bus can hold= to the total number of the student in a class)

x+y=9.......eqn 1

5x +45y=165....eqn 2

make x the subject of the formula in eqn 1

x+y=9

x= 9-y

substitute for x= 9-y in eqn 2

5(9-y)+45y=165

45-5y+45y=165

-5y+45y=165-45

40y=120

divide both sides by 40

40y÷40=120÷40

y=3

since y represent number of buses,the numbet of bus is 3

Also,substitute for y=3 in eqn 1

eqn 1 is x+y=9

x+3=9

x=9-3

x=6

therefore,the number of cars is 6.

3 0

3 years ago

The measure of ∠DAB equals 125º.

Assoli18 [71]

Firstly, we will draw diagram of this problem

we are given

∠DAB=125º

∠ACB=30º

Since, ∠DAB is exterior angle

∠ACB and ∠ABC are interior angles

and we know that

exterior angle is sum of two interior angles

so, we get

∠DAB=∠ACB +∠ABC

now, we can plug values

125º=30º+∠ABC

∠ABC=95º.............Answer

8 0

3 years ago

A rectangle in Quadrant II rotates 90° counterclockwise about the origin. In which Quadrant will the transformation lie?

OLga [1]

The transformation will lie in Quadrant III

8 0

3 years ago