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klemol [59]
3 years ago
7

If you place a 29-foot ladder against the top of a building and the bottom of the ladder is 24 feet from the bottom of the build

ing, how tall is the building? Round to the nearest tenth of a foot.
Mathematics
1 answer:
kobusy [5.1K]3 years ago
3 0

Answer:

16.3

Step-by-step explanation:

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Solve the problem.
Rufina [12.5K]
Answer is the B Sure let’s gooo
3 0
3 years ago
The following parts refer to the letters: LAMEFIREALARM. Recall that "word" means distinguishable letter arrangements. (a) How m
larisa86 [58]

Answer:

Step-by-step explanation:

The word "LAMEFIREALARM" word consists of

2L , 2M, 2E , 2R , 3A , F and I

no of words with the above letters such that M's are not together

=Total No of words- M's are together

Total no of words=\frac{13!}{4\times 2!\times 3!}=64,864,800

When M's are together . considering 2 M's as one

therefore there are \frac{12!}{3\times 2!\times 3!}=9,979,200

No of ways=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}=54,885,600

(b)No of ways such that M's are separated by at least 2 letters

at least  2 letter means 2 letter, 3 letter ......11 letters

So we have to subtract no of ways where there are 1 letter in between M's from total no of ways where 2 M's are not next to each other

No of ways in which there is 1 letter between 2 M's

This can be done by considering 11 cases

In first case Place first M in Starting Position and 2 M on third place

Second case place First M in 2 nd Position and second M on 4 th place

Similarly For 11th case

Place first M in 11th place and second M on 13th place

Total ways

=\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}

So , the total number of arrangements of the letters of the word LAMEFIREALARM where the two M's are separated by atleast two letters is

=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}-\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}

=45738000

7 0
3 years ago
Which values for n will make this expression true?
zavuch27 [327]
A because it rounds up
3 0
3 years ago
Read 2 more answers
In a standard normal distribution, what z value corresponds to 17% of the data between the mean and the z value?
hjlf
You're looking for a value z such that

\mathbb P(0

Because the distribution is symmetric, the value of z in either case will be the same.

Now, because the distribution is continuous, you have that

0.17=\mathbb P(0

The mean for the standard normal distribution is 0, and because the distribution is symmetric about its mean, it follows that \mathbb P(Z.

0.17=\mathbb P(Z

You can consult a z score table to find the corresponding score for this probability. It turns out to be z\approx0.4399.
4 0
3 years ago
Help me please with 3-111
LenKa [72]

Last Question

Because this may not be the question you want, I'll omit the first step which should be done with latex. The key to all of these except C is to invert the second fraction (turn the second fraction upside down) and multiply.

A

\dfrac{6}{5} * \dfrac{-2}{3}

=(6*-2) / (5*3) = - 12/15 = -4/5

B

\dfrac{7}{4} *\dfrac{5}{3}

= (7*5) / (4*3) = 35 / 12 = 2 11/12

C

Impossible to do 4/0 cannot be done.

D

\dfrac{-2}{3} /\dfrac{-5}{4}=\dfrac{-2}{3} *\dfrac{-4}{5}

= (-2*-4)/(3*5) =

8/15


4 0
3 years ago
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