40×4×4=640
b=20 h=4
using formula:
1/2×base×height
1/2×20×4=40
its says scale by factor 4:
b=80 h=16
using formula:
1/2×base×height
1/2×80×16=640
answer------>>>>640cm^2
You are finding 3 1/6 - 1 5/6.
To solve, you should first change it so that the numerator of the first fraction is greater than the numerator of the second. Note that both have the same denominator (6). Subtract as usual:
3 1/6 = 2 7/6
2 7/6 - 1 5/6 = 1 2/6
1 2/6 is your answer.
~
Answer:
7.6 seconds
Step-by-step explanation:
To solve this problem we can use the following equation:
S = So + 113*t + at^2/2
Where S is the final position, So is the inicial position, Vo is the inicial speed, a is the acceleration and t is the time.
In this problem, we have that S = 0, So = 65, Vo = 113 and a = -32 ft/s2 (The acceleration of gravity)
So we have that:
0 = 65 + 113t - 16t2
16t2 - 113t - 65 = 0
Using Bhaskara's formula, we have:
Delta = 113^2 + 4*65*16 = 16929
sqrt(Delta) = 130.11
t = (113 + 130.11) / (2*16) = 7.597 seconds
Rounding to nearest tenth, we have t = 7.6 seconds
Step-by-step explanation:
because VW || YZ, the 2 triangles are similar.
this is given by the rules of equal angles of intersecting lines with parallel lines. Z to V and Y to W would be such intersecting lines.
and therefore, the angle at W is the angle at Y, the angle at V is the angle at Z. and therefore both angles at A are equal.
so, for similar triangles the scaling factor between corresponding pairs of sides is the same for all sides.
e.g. the same scaling factor that converts 7.2 to 12, converts then also x to x+4.
7.2 × f = 12
f = 12/7.2 = 12/ 72/10 = 120/72 = 10/6 = 5/3
x × 5/3 = x + 4
5x = 3x + 12
2x = 12
x = 6
A to Y = x = 6
W to A = x + 4 = 6 + 4 = 10
