Answer:
27 weeks.
Step-by-step explanation:
You need to calculate the minimun common multiple between the three times.
1 week = 1^1 week
9 weeks = 3^2 weeks
27 weeks = 3^3 weeks
You take the 1 and the 3 with the biggest exponent and multiply. In this case is 1^1*3^3 = 27. So, in 27 weeks the pkanets will all be in alignment.
The slope form: y = mx + b
We have:
3x - 6y - 2 = 0 |add 6y to both sides
3x - 2 = 6y |divide both sides by 6
3x/6 - 2/6 = 6y/6
x/2 - 1/3 = y
y = 1/2 x - 1/3
Answer:
sin²2θ. (cos θ sin θ). cos 2θ
Step-by-step explanation:
finding g'(x)
g'(x)
= 4 (cosθsinθ)³ . { cosθ. (sinθ)' + sinθ. (cosθ)' }
- (cosθ)' = - sinθ
- (sinθ)' = cosθ
= 4 (cosθsinθ)³ { cosθ. cos θ + sinθ.(-sin θ)}
= 4 (cosθsinθ)³{ cos²θ - sin²θ}
- cos²θ - sin²θ = cos 2θ
- 2sinθ cosθ = sin 2θ
= (4 cosθ sinθ)². (cosθ sinθ). { cos²θ - sin²θ}
= <u>sin²2θ. (cos θ sin θ). cos 2θ</u>
Answer:
The approximated value of the standard deviation is 0.35.
Step-by-step explanation:
According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.
Then, the mean of the distribution of sample means is given by,

And the standard deviation of the distribution of sample means is given by,

The information provided is:
<em>n</em> = 100
<em>σ</em> = 3.5
<em>μ</em> = 66
As the sample size is quite large, i.e. <em>n</em> = 100 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample mean by the Normal distribution.
Then the approximated value of the standard deviation of sampling distribution of sample mean is:


Thus, the approximated value of the standard deviation is 0.35.