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Tomtit [17]
3 years ago
15

a number with 2 consecutive natural digits, how many units will it increase if written in reverse order. Detail solution pls

Mathematics
1 answer:
svetlana [45]3 years ago
5 0

Answer:

It will increase by 9 units.

Step-by-step explanation:

We can write the lowest number as  10a + (a + 1) and the highest is the reverse which is 10(a + 1) + a.

Subtracting:

10(a + 1) + a - (10a + a +1)

= 10a + 10 + a - 10a - a - 1

= 10a - 10a + a - a + 10 - 1

= 10 - 1

= 9.

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For the writer, <span><span>there are 20
1.       </span>1 + 39 = 40</span> <span><span>
2.       </span>2 + 38 = 40</span>
<span><span>3.       </span>3 + 37 = 40</span>
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12.   </span>12 + 28 = 40</span>
<span><span>13.   </span>13 + 27 = 40</span> <span><span>
14.   </span>14 + 26 = 40</span> <span><span>
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17.   </span>17 + 23 = 40</span> <span><span>
18.   </span>18 + 22 = 40</span> <span><span>
19.   </span>19 + 21 = 40</span> <span><span>
20.   </span>20 + 20 = 40</span>



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