Identify the Sl units of measurement for length (distance) and mass

Use the development of the atomic model to explain how scientists refine and build off each other’s findings, in order to develo

Veseljchak [2.6K]

We can use the atomic model to demonstrate the ways in which scientists refine and build off each other's findings because of the fact that once this model was created, it brought with it other models and inventions, such as the periodic table and other theories about our known universe.

7 0

4 years ago

What is the molar mas of zinc (Zn)? 6.02 g/mol 30.0 g/mol 48.7 g/mol 65.38 g/mol

My name is Ann [436]

It's in the periodic table.

See the attached picture. The number below 'Zn' is the molar mass. The closest answer choice is 65.38

3 0

4 years ago

Read 2 more answers

6. What is the pressure of 0.60 moles of a gas if its volume is 10.0 liters at 35.0°C?

denis-greek [22]

Answer: The pressure inside the cylinder will be 1.5 atm. The pressure can be calculated using the Ideal Gas Equation which relates the pressure, volume, temperature, and amount of gas to each other.

Further Explanation

The Ideal Gas Equation is:

$PV = nRT$

where:

P - pressure (in atm)

V - volume (in L)

n - amount of gas (in moles)

R - universal gas constant $0.08206 \frac{L-atm}{mol-K}$

T - temperature (in K)

In the problem, we are given the values:

P = ?

V = 10.0 L (3 significant figures)

n = 0.60 moles ( 2 significant figures)

T = 35.0 degrees Celsius (3 significant figures)

We need to convert the temperature to Kelvin before we can use the Ideal Gas Equation. The formula to convert from degree Celsius to Kelvin is:

$Temperature \ in \ Kelvin = Temperature\ in \ Celsius \ + \ 273.15$

Therefore, for this problem,

$Temperature\ in \ K = 35.0 +273.15\\Temperature\ in \ K = 308.15$

Solving for P using the Ideal Gas Equation:

$P = \frac{nRT}{V} \\P = \frac{(0.60\ mol) \ (0.08206 \ \frac{L-atm}{mol - K}) \ (308.15\ K) \ }{10.0 \ L} \\P = 1.51\ atm$

The least number of significant figures is 2, therefore, the final answer must have only 2 significant figures.

Learn More

1. Learn more about Boyle's Law brainly.com/question/1437490

2. Learn more about Charles' Law brainly.com/question/1421697

3. Learn more about Avogadro's Law brainly.com/question/1964205

Keywords: Ideal Gas Law, Gas Pressure

7 0

4 years ago

Molten lava from a volcano includes pockets of gases. A sample of lava contains 0.75 L of water vapour at 1170°C. What volume wi

Lesechka [4]

Charle's law states the relationship between the temperature and the volume of the gas. The final volume occupied at 120 °C is 0.20 L.

<h3>What is Charle's law?</h3>

Charle's law is the ideal gas law that states the relationship between the volume of the gas occupied at a temperature.

Given,

V1 = 0.75 L

T1 = 1443 .15 K

T2 = 393.15 K

The final volume is calculated as:

(V1 × T2) ÷ T1

= 0.75 × 393.15 ÷ 1443.15

= 0.20 L

Therefore, 0.20 L is the final volume.

Learn more about Charle's law here:

brainly.com/question/14517633

#SPJ1

4 0

2 years ago

Consider four different samples: aqueous NaBr, molten NaBr, aqueous NaF, and molten NaF. Current run through each sample produce

EastWind [94]

Answer:

Aqueous NaBr - oxygen gas

Molten NaBr - liquid bromine

Aqueous NaF- oxygen gas

Molten NaF - Flourine gas

Explanation:

In electrolysis process, anode is the positive electrode and cathode is the negative electrode.

Hence negative ions are attracted towards anode and gets oxidized.

When more than one type of ion is present , the ion which gets deposited is decided by the <u>discharge potential.</u>

Discharge potential is the voltage at which an ion is discharged.The ion that requires less energy to get deposited has low discharge potential.

Hence ion with low discharge potential gets deposited.

Discharge potential is in the order: $F^->Br^->OH^-$

In aqueous NaBr , there are two negative ions:Br- and OH-

OH- is oxidized to oxygen gas as OH- has lower discharge potential.

2. In molten NaBr, Br- is the only negative ion and liquid bromine is produced at anode.

3. In aqueous NaF, OH- and F- are the anions present. Clearly oxygen gas is produced at anode as OH- has lower discharge potential.

4. In molten NaF only anion present is F- and hence flourine gas is produced at anode.

7 0

3 years ago