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Ket [755]
3 years ago
13

Paul has an 50​% methyl alcohol solution. He wishes to make a gallon of a solution by mixing his methyl alcohol solution with wa

ter. If 128 ​ounces, or a​ gallon, of solution should contain 5​% methyl​ alcohol, how much of the 50​% methyl alcohol solution and how much water must be​ mixed?
Chemistry
1 answer:
stira [4]3 years ago
7 0

Answer:

To make one gallon of 5% methyl alcohol we require 115.2oz of water and 12.8oz of 50% methyl alcohol solution

Explanation:

Required solution = 1 gallon of 5% methyl alcohol or1 gallon 5/100 moles per dm3 of methyl alcohol

Number of moles in required solution = 0.05moles/dm3 × 1gallon

Where 1 gallon = 0.00378dm3

= 0.05moles/dm3 × 0.00378dm3 = 1.892×10-4 moles

 

The quantity of the  50% solution with Paul required is given by

50% = 50/100 = 0.5 moles/dm3 

Volume of 50% solution of methyl alcohol that contains 1.892×10-4 moles

= concentration = (Number of moles)/(volume of dm3) of solution thus

Volume of solution = (Number of moles)/(concentration)

1.892/0.5 =3.785×10-4dm3 of the 50% solution is required to make 1 gallon of 5% solution

 

3.785×10-4dm3 = 12.8oz

Thus to make 1 gallon or 128oz solution of 5% alcohol requires

128oz - 12.8 oz = 115.2oz of water and 12.8oz of 50% methyl alcohol solution

 

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Answer:

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Explanation:

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3 years ago
What is the mass of 3.62X10^24 molecules of methanol
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Answer:

Recycling and reuse of materials

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Answer:

See explanation.

Explanation:

Hello there!

In this case, considering the given information, it is not possible to figure out such order of reaction with respect to water as it is not involved in the given chemical reaction:

2E(g)+ F(g)+O(g)_

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Regards!

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