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jenyasd209 [6]
3 years ago
9

6. What is the pressure of 0.60 moles of a gas if its volume is 10.0 liters at 35.0°C?

Chemistry
1 answer:
denis-greek [22]3 years ago
7 0

Answer: The pressure inside the cylinder will be 1.5 atm. The pressure can be calculated using the Ideal Gas Equation which relates the pressure, volume, temperature, and amount of gas to each other.  

Further Explanation

The Ideal Gas Equation is:  

PV = nRT

where:

P - pressure (in atm)

V - volume (in L)

n - amount of gas (in moles)

R - universal gas constant 0.08206 \frac{L-atm}{mol-K}

T - temperature (in K)

In the problem, we are given the values:

P = ?

V = 10.0 L (3 significant figures)

n = 0.60  moles  ( 2 significant figures)

T = 35.0 degrees Celsius (3 significant figures)

We need to convert the temperature to Kelvin before we can use the Ideal Gas Equation. The formula to convert from degree Celsius to Kelvin is:

Temperature \ in \ Kelvin = Temperature\ in \ Celsius \ + \ 273.15

Therefore, for this problem,

Temperature\ in \ K = 35.0 +273.15\\Temperature\ in \ K = 308.15

Solving for P using the Ideal Gas Equation:

P = \frac{nRT}{V} \\P = \frac{(0.60\ mol) \ (0.08206 \ \frac{L-atm}{mol - K}) \ (308.15\ K) \ }{10.0 \ L} \\P = 1.51\ atm

The least number of significant figures is 2,  therefore, the final answer must have only 2 significant figures.

Learn More

1. Learn more about Boyle's Law brainly.com/question/1437490  

2. Learn more about Charles' Law brainly.com/question/1421697

3. Learn more about Avogadro's Law brainly.com/question/1964205

Keywords: Ideal Gas Law, Gas Pressure

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Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

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Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

P\cdot V = n\cdot R\cdot T,

\displaystyle V = \frac{n\cdot R\cdot T}{P}.

where

  • P is the pressure of the gas,
  • V is the volume of the gas,
  • n is the number of moles of particles in this gas,
  • R is the ideal gas constant, and
  • T is the absolute temperature of the gas (in degrees Kelvins.)

The numerical value of R will be 8.314 if P, V, and T are in SI units. Convert these values to SI units:

  • P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa;
  • V shall be in cubic meters, \rm m^{3};
  • T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K.

Apply the ideal gas law:

\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}.

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