3 years ago

A board is 74.93 centimeters long. How long is the board in inches use the following conversation: 1 inch 2.54 centimeters

Mathematics

2 answers:

soldi70 [24.7K]3 years ago

4 0

It would be 29.5 inches

enot [183]3 years ago

3 0

Your answer is 29.5 inches

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The difference between the roots of the equation 3x^2+bx+10=0 is equal to 4 1/3 . Find b.

telo118 [61]

$\textit{quadratic formula}\\
{{ 3}}x^2{{ +b}}x{{ +10}}=0
\qquad \qquad 
x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}
\\ \quad \\
meaning\implies x=\cfrac{-b\pm\sqrt{b^2-4(3)(10)}}{2(3)}\qquad now
\\ \quad \\
\cfrac{-b\pm\sqrt{b^2-4(3)(10)}}{2(3)}\to 
\begin{cases}
\cfrac{-b+\sqrt{b^2-4(3)(10)}}{2(3)}
\\ \quad \\

\cfrac{-b-\sqrt{b^2-4(3)(10)}}{2(3)}
\end{cases}\impliedby \textit{two roots}$

$\textit{and their root difference is }4\frac{1}{3}\implies \cfrac{13}{3}\qquad so
\\ \quad \\
\left[ \cfrac{-b+\sqrt{b^2-4(3)(10)}}{2(3)} \right]-\left[ \cfrac{-b-\sqrt{b^2-4(3)(10)}}{2(3)} \right]=\cfrac{13}{3}
\\ \quad \\
\left[ \cfrac{-b+\sqrt{b^2-4(3)(10)}}{6} \right]+\left[ \cfrac{+b+\sqrt{b^2-4(3)(10)}}{6} \right]=\cfrac{13}{3}
\\ \quad \\
\cfrac{-b+\sqrt{b^2-4(3)(10)}+b+\sqrt{b^2-4(3)(10)}}{6}=\cfrac{13}{3}
\\ \quad \\
\cfrac{2\sqrt{b^2-4(3)(10)}}{6}=\cfrac{13}{3}$

and I'm pretty sure you can take it from there

7 0

3 years ago

Round 452,906 to the nearest hundred thousand

NeX [460]

500,000

(5 or above, give it a shove)

4 0

3 years ago

Read 2 more answers

Compute the square root of√144

zloy xaker [14]

The square root of 144 is 12