Help I dont understand this
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
The range of a function is the set of all possible values it can produce.
For example, consider the function
No matter what value we give to x, the function is always positive:
If x is 2, then the function returns x squared or 4.
If x is negative 2, then it still produces 4 since -2 times -2 is positive 4.
So the range of the function is
"all real numbers greater than or equal to zero".
Answer:
a = 4
b = -2
Step-by-step explanation:
If the given function is continuous at x = 1
And for the continuity of the function at x = 1,
Therefore, (a + b) = 2 -------(1)
If the function 'f' is continuous at x = 2,
Therefore,
2a + b = 6 -----(2)
Subtract equation (1) from (2),
(2a + b) - (a + b) = 6 - 2
a = 4
From equation (1),
4 + b = 2
b = -2
The standard form for a parabola is (x - h)2 = 4p (y - k), where the focus is (h, k + p) and the directrix is y = k - p. If the parabola is rotated so that its vertex is (h,k) and its axis of symmetry is parallel to the x-axis, it has an equation of (y - k)2 = 4p (x - h), where the focus is (h + p, k) and the directrix (d)
is x = h - p.
So directrix is: y = k - p and the focus is at:
(h, k+p)
Since our focus is: (1, 3) and directrix is: y = 1,
thus h = 1, k+p = 3, and k-p = 1
Therefore k = 3-p, 3-p-p = 1, k = 3-p = 3-1 = 2
3-2p = 1, -2p = -3+1, -2p = -2, p = 1
Now we plug p, k, & h into standard form:
(x - h)2 = 4p (y - k)
y = 1/4 (x-1)^2 + 2
is x = h - p.
So directrix is: y = k - p and the focus is at:
(h, k+p)
Since our focus is: (1, 3) and directrix is: y = 1,
thus h = 1, k+p = 3, and k-p = 1
Therefore k = 3-p, 3-p-p = 1, k = 3-p = 3-1 = 2
3-2p = 1, -2p = -3+1, -2p = -2, p = 1
Now we plug p, k, & h into standard form:
(x - h)2 = 4p (y - k)
y = 1/4 (x-1)^2 + 2