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geniusboy [140]
3 years ago
12

True or false questions

Mathematics
1 answer:
Bond [772]3 years ago
8 0

Answer:

correct me if i'm wrong but i think

1.False

2.False

3.True

4.True

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If 3x^2 + y^2 = 7 then evaluate d^2y/dx^2 when x = 1 and y = 2. Round your answer to 2 decimal places. Use the hyphen symbol, -,
S_A_V [24]
Taking y=y(x) and differentiating both sides with respect to x yields

\dfrac{\mathrm d}{\mathrm dx}\bigg[3x^2+y^2\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[7\bigg]\implies 6x+2y\dfrac{\mathrm dy}{\mathrm dx}=0

Solving for the first derivative, we have

\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x}y

Differentiating again gives

\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0

Solving for the second derivative, we have

\dfrac{\mathrm d^2y}{\mathrm dx^2}=-\dfrac{3+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}y=-\dfrac{3+\frac{9x^2}{y^2}}y=-\dfrac{3y^2+9x^2}{y^3}

Now, when x=1 and y=2, we have

\dfrac{\mathrm d^2y}{\mathrm dx^2}\bigg|_{x=1,y=2}=-\dfrac{3\cdot2^2+9\cdot1^2}{2^3}=\dfrac{21}8\approx2.63
3 0
3 years ago
Can you help me with this
ahrayia [7]

Step-by-step explanation:

1. YES

2. YES

3. YES

4. NO

this is a decimal that neither terminates nor repeats.

5 0
3 years ago
How to didvide6 divided by 8,654
Lelechka [254]

Answer: 0.0007

Step-by-step explanation:

6/8654

3 0
3 years ago
Ms. Brown's class is learning about banks, so she creates one in her classroom. All students start with $75 in their accounts. L
Katen [24]

Answer:

can you show the students balance at the end of activity ??

Step-by-step explanation:

4 0
3 years ago
60 + 84<br> the sum of the numbers as a product of their GCF is?
Deffense [45]
The sum is the gcf, if 60 plus 84 is 148 then wouldn't it be 148 that's what they all have in common, you can use a calculator to figure this out like say 148 times 2 equals 296, divide 296 by 60. Does it go in?
7 0
3 years ago
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