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Llana [10]
3 years ago
11

What ray is a common side of

Mathematics
2 answers:
anyanavicka [17]3 years ago
5 0
Your answer would be Ray OB

Hope this helps!
shepuryov [24]3 years ago
3 0
The correct answer is : ray OB
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What is the answer to these question?
Natali5045456 [20]

Answer:

2.  y = 7/2 x -2

3.   y = 3/4x-1

Step-by-step explanation:

points (0,-2)  (4,12)

slope = (y2-y1)/(x2-x1)

slope = (12--2)/(4-0)

    = (12+2)/4

   = 14/4 = 7/2

the slope is 7/2 and the y intercept is -2

y = mx+b

y = 7/2 x -2


points (0,-1)  (4,2)

slope = (y2-y1)/(x2-x1)

slope = (2--1)/(4-0)

    = (2+1)/4

   = 3/4

the slope is 3/4 and the y intercept is -1

y = mx+b

y = 3/4x-1

3 0
3 years ago
26% ≈<br> 84 ≈ 80 <br> So, 26% of 84 ≈
iVinArrow [24]
26% of 84 = 21.84. hope that helps
5 0
3 years ago
Read 2 more answers
What is the quotient? StartFraction 3 y 2 Over 3 y EndFraction divided by StartFraction 6 y squared 4 y Over 3 y 2 EndFraction S
Dima020 [189]

The quotient of the expression is \frac{1}{2y}

The expression is given as:

\frac{3y^2}{3y} \div \frac{6y^4}{3y^2}

Divide 3y^2 by 3y

\frac{3y^2}{3y} \div \frac{6y^4}{3y^2} = y \div \frac{6y^4}{3y^2}

Rewrite the equation as a product

\frac{3y^2}{3y} \div \frac{6y^4}{3y^2} = y \times \frac{3y^2}{6y^4}

Divide 6 by 3

\frac{3y^2}{3y} \div \frac{6y^4}{3y^2} = y \times \frac{y^2}{2y^4}

Multiply y and y^2

\frac{3y^2}{3y} \div \frac{6y^4}{3y^2} = \frac{y^3}{2y^4}

Divide y^3 by y^4

\frac{3y^2}{3y} \div \frac{6y^4}{3y^2} = \frac{1}{2y}

Hence, the quotient of the expression is \frac{1}{2y}

Read more about quotients at:

brainly.com/question/12217706

8 0
2 years ago
How do i do this equation <br> -3(-2y-4)-5y-2=
sp2606 [1]

Answer:

combined like terms and then follow  the order of operations.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help me this is tough
kobusy [5.1K]

Answer:

12 basil leaves.

Step-by-step explanation: First you divide 32 by 8 and you should get 4 then you multiply 4 by 3 and you get 12 aka your answer

6 0
3 years ago
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