What ray is a common side of
2 answers:
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<u>Answer: </u>
The fraction of the bleachers filled with the home team is
<u>Solution: </u>
Given that,
The bleachers at the football game are
In those bleachers of the fans are rooting for the home team
So, the fans that are filled with the home team is \left(\left(\frac{7}{8}\right) \times\left(\frac{1}{2}\right)\right)
Hence, the required fraction is \left(\left(\frac{7}{8}\right) \times\left(\frac{1}{2}\right)\right)
Removing the brackets we get,
\frac{7 \times 1}{8 \times 2}
=
The required fraction is