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7:45 A.M> is what time in military time?

Black_prince [1.1K]

0745 legit is 7:45 in military time

8 0

3 years ago

Read 2 more answers

Does someone know this one please :)

GarryVolchara [31]

6/11(5/6)+2/11(5)
=5/11+10/11
=15/11

3 0

2 years ago

A recent survey of 128 high school students indicated the following information about release times from school. -35 percent wan

wlad13 [49]

Answer:

The interval is for those that want to get out earlier is between 43 student to 47 students

The interval is for those that want to get out later is between 48 student to 50 students

Step-by-step explanation:

Given that:

sample size n=128

Probability of those that want to get out earlier = 0.35.

The mean = n × probability = 0.35 × 128 = 44.8 ≈ 45

Margin of error = 4% = 0.04 × 44.8 = 1.79 ≈ 2

Therefore the interval = mean ± Margin of error = 45 ± 2 = (43, 47)

The interval is for those that want to get out earlier is between 43 student to 47 students

Probability of those that want to get out later = 0.39.

The mean = n × probability = 0.39 × 128 = 49.92 ≈ 50

Margin of error = 4% = 0.04 × 50 = 2

Therefore the interval = mean ± Margin of error = 50 ± 2 = (48, 52)

The interval is for those that want to get out later is between 48 student to 50 students

the group that wants to get out of school earlier to win after all the votes are counted if those that have no opinion decide that they want to go earlier

5 0

2 years ago

United Flight 15 from New York's JFK airport to San Francisco uses a Boeing 757-200 with 182 seats. Because some people with res

Tcecarenko [31]

Answer:

There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.

Step-by-step explanation:

For each passenger, there are only two outcomes possible. Either they show up for the flight, or they do not show up. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

A probability is said to be unusually low if it is lower than 5%.

For this problem, we have that:

There are 200 reservations, so $n = 200$ .

A passenger consists in a passenger not showing up. There is a .0995 probability that a passenger with a reservation will not show up for the flight. So $\pi = 0.0995$ .

Find the probability that when 200 reservations are accepted for United Flight 15, there are more passengers showing up than there are seats available.

X is the number of passengers that do not show up. It needs to be at least 18 for the flight not being overbooked. So we want to find $P(X < 18)$ , with $\pi = 0.0995, n = 200$ . We can use a binomial probability calculator, and we find that:

$P(X < 18) = 0.2927$ .

There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.

5 0

2 years ago

Identify one unique decimal that you encounter regularly during the week and how it affects you or not in your daily life. your

Tpy6a [65]

A unique decimal that I encounter regularly is "0.05". I encounter this almost every day, when I go to the store to buy something, the saleslady gives me $0.05 as change. When I go home and put some of my extra money in my piggy bank, I hold a $0.05 in my hand.

5 0

2 years ago