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tatyana61 [14]
3 years ago
6

Match the system of linear equations, to its graph.

Mathematics
1 answer:
kykrilka [37]3 years ago
5 0

Answer:

The answer is the second graph, Option 2

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An unbalanced scale with 8 blocks on the left side of the scale and 3 blocks on the right side of the scale
klasskru [66]

Answer:

Take away 5 blocks from the left side

Step-by-step explanation:

Take away 5 blocks from the left side and then you will get 3 blocks on both sides then the scale will be balanced.

5 0
3 years ago
The first group was responsible for making 160 suits while the second group was responsible for making 25% fewer suits in the sa
egoroff_w [7]
First group rate is x+10, Second is x
First group made 160, Second made 120
Time the first group will take is 160/x+10, and second is 120/x
Equation is: 160/x+10 + 4 = 120/x
x=10, x=-30
The second group made 10 suits everyday.


3 0
3 years ago
Please I need help I don’t understand this!
Alex_Xolod [135]
When reflected across the y axis, the x coordinate becomes the opposite but the y coordinate stays the same, so N is (2, -5)
when reflected across the x axis, the y coordinate becomes the opposite but the x coordinate stays the same, so R is (2, 5)
8 0
3 years ago
A ladder 13 feet long leans against a building. The bottom of the ladder is 5 feet away from the base of the building.How far up
seraphim [82]

Answer:

12 ft

Step-by-step explanation:

4 0
3 years ago
At a sport clubhouse the coach wants to rope off a rectangular area that is adjacent to the building. He uses the length of the
Furkat [3]

Answer:

w < 8 meters ( w must be greater than 0 because length cannot be 0)

Step-by-step explanation:

One side with building is 23 meters, the other opposite side also will be 23 meters (with rope).

Let width (remaining 2 sides) be "w", he has AT MOST 39 meters of rope, so we can write:

Rope Needed = 23 + 2w < 39

Simplifying:

23 + 2w < 39\\2w < 39 - 23\\2w < 16\\w < 8

The range of possible values of w is  w meters (of course w has to be greater than 0)

5 0
3 years ago
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