3 years ago

Match the system of linear equations, to its graph.

Mathematics

1 answer:

kykrilka [37]3 years ago

5 0

Answer:

The answer is the second graph, Option 2

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Susan has been on a bowling team for 14 years. After examining all of her scores over that period of time, she finds that they f

elixir [45]

Answer:

Step-by-step explanation:

Let X be the random variable that represents a score of Susan. We know that X has a normal distribution with average score of 225 and a standard deviation of 13. For n = 16 games, the average score $\bar{X}$ has a normal distribution with mean of 225 and a standard deviation of $13/\sqrt{16}=13/4=3.25$ . Besides, the z-score related to 220 is (220-225)/3.25=-1.5385, and the z-score related to 228 is (228-225)/3.25= 0.9231. Therefore, we are looking the probability $P(220 < \bar{X} < 228) = P(-1.5385 < Z < 0.9231) = P(Z < 0.9231) - P(Z < -1.5385)$ = 0.76

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3 years ago

Anusha is walking on a hiking trail at a rate of Three-fourths miles in One-fourth hour. At this rate, how far will Anusha walk

grandymaker [24]

Answer:

Step-by-step explanation:

3/4 + 3/4 + 3/4 + 3/4 = 12/4 = 3. She will walk 3 miles in an hour.

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3 years ago

What's the equivalent algebraic expression?

densk [106]

-10c+70, just distribute the the -10 to everything in the expression

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3 years ago

(2^8 x 3^−5 x 6^0)−2 x 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 x 2^28

Veronika [31]

$(2^8\cdot3^{-5}\cdot6^0)^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot2^{28}\\\\=(2^8)^{-2}\cdot(3^{-5})^{-2}\cdot1^{-2}\cdot\dfrac{(3^{-2})^4}{(2^3)^4}\cdot2^{28}\\\\=2^{-16}\cdot3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot2^{28}\\\\=2^{-16}\cdot2^{28}\cdot2^{-12}\cdot3^{10}\cdot3^{-8}\\\\=2^{-16+28+(-12)}\cdot3^{10+(-8)}\\\\=2^0\cdot3^2=1\cdot9=\boxed{9}\\\\Used:\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{n\cdot m}\\\\a^n\cdot a^m=a^{n+m}\\\\a^{-n}=\dfrac{1}{a^n}$

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3 years ago

Read 2 more answers

work out the area of a circle with diameter 1.8cm. Take <img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" al

ankoles [38]

Area of a circle is pi x r ^2

R = diameter/2

R = 1.8/2 = 0.9

Area = 3.142 x 0.9^2

Area = 2.5 square cm.

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3 years ago