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enot [183]
2 years ago
11

Find all integer solutions to the equation 91x + 329y = 49.

Mathematics
1 answer:
Vadim26 [7]2 years ago
4 0

Answer:

dont waste points get wolfframAlpha

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Jan has 37.50 tickets to a concert concert 5.25 each how many tickets can Jan buy
alexandr1967 [171]
Number of tickets= X
To find the number of tickets, divide the money Jan has with the cost of each ticket.
So,
X =37.50/ 5.25=7.14

But since she can't buy part of a ticket, Jan can buy 7 tickets
4 0
2 years ago
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Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-6, -4),A(−6
Lelu [443]

Answer:

8

Step-by-step explanation:

8 0
3 years ago
In the equation y = 3x – 1, what is the value of y when x equals –3?
emmainna [20.7K]

Answer:

D. –10

Step-by-step explanation:

Given equation:

y = 3x – 1

what is the value of y when x equals –3?

Substitute x = -3 into the equation to find y

y = 3x – 1

= 3(-3) - 1

= -9 - 1

= -10

y = -10

The correct answer is D. –10

8 0
3 years ago
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A machine makes 300 boxes in 15 minutes which expression equals the unit rate in box per hour
gregori [183]

Answer:

20 per min

Step-by-step explanation:

6 0
3 years ago
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A genetic experiment involving peas yielded one sample of offspring consisting of 430 green peas and 155 yellow peas. Use a 0.05
Dimas [21]

Answer:

the null and alternative hypothesis are

H_{0}: p=0.24

H_{a}: p≠0.24

Test statistic is 1.416.

P-Value is 0.1568

We fail to reject the null hypothesis under 0.05 significance level

<em>At 0.05 significance</em> we cannot say that the proportion of offspring peas will be yellow is not 0.24 (24%)

Step-by-step explanation:

Let p be the proportion of offspring peas will be yellow. Then,

H_{0}: p=0.24

H_{a}: p≠0.24

test statistic can be calculated as

z=\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } } where

  • p(s) is the sample proportion of yellow offspring peas (\frac{155}{155+430} =0.265
  • p is the proportion of yellow offspring peas assumed under null hypothesis. (0.24)
  • N is the sample size (585)

Test statistic is z=\frac{0.265-0.24}{\sqrt{\frac{0.24*0.76}{585} } } ≈ 1.416.

Using z-table, we can find that P-Value is 0.1568

We fail to reject the null hypothesis under 0.05 significance level since 0.157>0.05

We can conclude that <em>at 0.05 significance</em> we cannot say that the proportion of offspring peas will be yellow is not 0.24 (24%)

6 0
3 years ago
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