I’m not 100% sure but it could be 225 and 328. Adding those together you get a sum of 553.
Hope this helped! Mark me brainliest if you’d like, im tryna get too expert!
Hello!
So, this is quite the complex question, and here are the following steps:
What is the quotient of ![\frac{6-3\sqrt[3]{6}}{\sqrt[3]{9}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B6-3%5Csqrt%5B3%5D%7B6%7D%7D%7B%5Csqrt%5B3%5D%7B9%7D%7D%20%20)
?
![\frac{(6 - 3\sqrt[3]{6})\sqrt[3]{9^{2}}}{9}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%286%20-%203%5Csqrt%5B3%5D%7B6%7D%29%5Csqrt%5B3%5D%7B9%5E%7B2%7D%7D%7D%7B9%7D%20%20%20%20%20)
(rationalize the denominator)
![\frac{3(2 -\sqrt[3]{6})\sqrt[3]{9^{2}}}{9}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%282%20-%5Csqrt%5B3%5D%7B6%7D%29%5Csqrt%5B3%5D%7B9%5E%7B2%7D%7D%7D%7B9%7D%20%20%20%20%20)
(factor 3 from the expression)
![\frac{(2-\sqrt[3]{6})\sqrt[3]{9^{2}}}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%282-%5Csqrt%5B3%5D%7B6%7D%29%5Csqrt%5B3%5D%7B9%5E%7B2%7D%7D%7D%7B3%7D%20%20%20%20%20)
(reduce the fraction with 3)
![\frac{2\sqrt[3]{9^{2}}-\sqrt[3]{9^{2}}}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%5Csqrt%5B3%5D%7B9%5E%7B2%7D%7D-%5Csqrt%5B3%5D%7B9%5E%7B2%7D%7D%7D%7B3%7D%20%20%20%20%20%20%20%20)
(distributive property)
![\frac{2\sqrt[3]{81}-\sqrt[3]{486}}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%5Csqrt%5B3%5D%7B81%7D-%5Csqrt%5B3%5D%7B486%7D%7D%7B3%7D%20)
(simplify 3 · 9²)
![\frac{6\sqrt[3]{3}-3\sqrt[3]{18}}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B6%5Csqrt%5B3%5D%7B3%7D-3%5Csqrt%5B3%5D%7B18%7D%7D%7B3%7D%20%20%20%20)
(simplify the radical)
![\frac{3(2\sqrt[3]{3}-3\sqrt[3]{18})}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%282%5Csqrt%5B3%5D%7B3%7D-3%5Csqrt%5B3%5D%7B18%7D%29%7D%7B3%7D%20%20%20%20)
(factor 3 from the expression)
![2\sqrt[3]{3}-\sqrt[3]{18}](https://tex.z-dn.net/?f=%202%5Csqrt%5B3%5D%7B3%7D-%5Csqrt%5B3%5D%7B18%7D%20%20%20%20)
(reduce the fraction)
The answer, is simply, choice A, ![2\sqrt[3]{3} -\sqrt[3]{18}](https://tex.z-dn.net/?f=%202%5Csqrt%5B3%5D%7B3%7D%20-%5Csqrt%5B3%5D%7B18%7D%20%20)
≈ 0.263758.
You can solve this by using the system of equations.
Jan - 4.95 = 2H + 3C
Wayne - 5.45 = 3H + 2C
Use elimination.
-3(2H + 3C = 4.95)
2(3H + 2C = 5.45)
Solve. And you'll get:
-6H + (-9C) = -14.85
6H + 4C = 10.9
Cross out -6H and 6H because they cancel out. And you're left with:
-9C = -14.85
4C = 10.9
Add -9C with 4C, and -14.85 with 10.9.
-5C = -3.95
Divide each side with -5.
C = $0.79
Now to figure out what H is, just substitute the C in one of the equations with 0.79.
5.45 = 3H + 2(0.79)
5.45 = 3H + 1.58
-1.58 -1.58
3.87 = 3H
3.87/3 = 3/3(H)
1.29 = H
Finished!
With the help of the given equation, we know that the automobile is worth $12528.15 after four years.
<h3>
What are equations?</h3>
- A mathematical equation is a formula that uses the equals sign to represent the equality of two expressions.
- a formula that expresses the connection between two expressions on each side of a sign.
- Typically, it has a single variable and an equal sign.
- Like this: 2x - 4 Equals 2.
- In the above example, the variable x exists.
So, the equation of depreciation: y = A(1 - r)∧t
The current value is y.
A is the initial cost.
r is the depreciation rate.
t is the time in years, and
In four years, we must ascertain the present value.
Now,
y = $24000(1 - 0.15)⁴
y = 24000(0.85)⁴
y = 24000 × 0.52200625
y = 12528.15
Therefore, with the help of the given equation, we know that the automobile is worth $12528.15 after four years.
Know more about equations here:
brainly.com/question/28937794
#SPJ4
Complete question:
The general equation for depreciation is given by y = A(1 – r)t, where y = current value, A = original cost, r = rate of depreciation, and t = time, in years. The original value of a car is $24,000. It depreciates 15% annually. What is its value in 4 years? $
Answer:
65mm
Step-by-step explanation:
From the Pythagorean theorem, we can write it as sqrt(60^2+25^2) which is 65.
