An Aibo costs $2,899.99. This includes a toy ball, a charging station, and several years of AI cloud service, which helps it lea
rn. For how long is that service free? How do you know?
1 answer:
Answer:
See Below
Step-by-step explanation:
The attached graph shows the cumulative costs of owning an AIBO.
$2899.99 (about $2900) includes fixed cost of Toy Ball, Charging Station
Several years of AI cloud service is a variable cost because this is changing and it helps the robot dog "learn". It is going to cost after some time. But how long?
Looking at the cost of an AIBO, we see that until 3 years, the cost line is veyr close to 3000 dollars, we can say 2899.99 dollars. After 3 years, the cost rises with a slope. Now, this is the cost of AI cloud service being IMPOSED after first 3 years of being "free".
Thus,
We can say that service is free for first 3 years. We know by looking at the graph shown.
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See attached picture for solution:
Answer:
I think this is the right answer but last two signs are incorrect
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Answer:
Explanation:
When solving systems of equations in three variables, pick two equations to work with first, solve for both variables, plug them into one of the equations you first started on, then in the end, put them altogether:
{-6<em>x</em> + 5<em>y</em> + 2<em>z</em> = -11 ←
{-2<em>x</em> + <em>y</em> + 4<em>z</em> = -9 We can eliminate the<em> </em><em>y-</em><em>values</em><em> </em>obviously
{4<em>x</em> - 5<em>y</em> + 5<em>z</em> = -4 ←
{-6<em>x</em> + 5<em>y</em> + 2<em>z</em> = -11
{4<em>x</em> - 5<em>y</em> + 5<em>z</em> = -4
___________________
-2<em>x</em> + 7<em>z</em> = -15
- 7<em>z</em> -7<em>z</em>
______________
-2<em>x</em> = -15 - 7<em>z</em>
___ ________
-2 -2
<em>x</em> = 7½ + 3½<em>z</em>
-2[7½ + 3½<em>z</em>] + <em>y</em> + 4<em>z</em> = -9
-15 - 7<em>z</em> + <em>y</em> + 4<em>z</em> = -9
-15 - 3<em>z</em> + <em>y</em> = -9
+15 + 15
_______________
-3<em>z</em> + <em>y</em> = 6
+3<em>z</em> + 3<em>z</em>
<em>y</em> = 6 + 3<em>z</em> [Plug in -1 for <em>z</em><em> </em>to give you the y-value of 3; 3 = <em>y</em>; since you now have both <em>z</em><em> </em>and <em>y</em><em> </em>terms, plug in these terms back into all three equations above to get the x-value of 4.]; 4 = <em>x</em> ⤻
-6[7½ + 3½<em>z</em>] + 5[6 + 3<em>z</em>] + 2<em>z</em> = -11
-45 - 21<em>z</em> + 30 + 15<em>z</em> + 2<em>z</em> = -11
-15 - 4<em>z</em> = -11
+15 + 15
_____________
-4<em>z</em> = 4
___ __
-4 -4
<em>z</em> = -1 [Plug this into the equation for <em>y</em>]⤻
I am joyous to assist you anytime.