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2 years ago

Whats the area of the lawn in this shape

Mathematics

1 answer:

Licemer1 [7]2 years ago

7 0

Answer:

208 ft

Step-by-step explanation:

in order to do this we need to find the area of the retangle:

(l x w) 14x20= 280ft

then the area of the rectangle:

a^2 + b^2 = c^2 ( hypotenus lenght )

c= 8.5

now we can plug in to find the area of the triangle, which is 12 (11.99)

then the area of the trapezium= 60

finally we can find the answer

280 - (60+12)= 208 ft :)

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What is the value of x in the inequality? 7+2x/5 -3 a. x>-8/3 b. x<-8/3 c. x>8/3 d. x<-3/8

Len [333]

D.x←-3\8 I think!!!!!

5 0

3 years ago

A piano teacher gives lessons that are each Three-fourths hour long. How many piano lessons can the teacher fit into a 12-hour w

tino4ka555 [31]

Answer:

16 lessons

Step-by-step explanation:

12 divided by .75 = 16

3 0

2 years ago

Read 2 more answers

Which graph represents y=1/2x+2 please help!!

wel

Answer:

Step-by-step explanation:

Let’s first look at the y-intercept. Since the equation is in y = mx + b form, we know that m is the slope and b is the y-intercept, so the slope is 1/2 and the y-intercept is 2, or (0,2). We can narrow down our search by noticing that C and D don’t intersect (0,2). That leaves A and B.

The slope is calculated by (y_1 - y_2)/(x_1 - x_2) given points (x_1, y_1) and (x_2, y_2). The slope for A is (4-0)/(2-(-2)) = 4/4 = 1 and the slope for B is (2-0)/(0-(-4)) = 2/4 = 1/2. The slope of B matches the slope that we are looking for. So, the answer is B.

8 0

2 years ago

The height of Atlas V rocket used for space lifts was 205 feet. What is the height of a model of Atlas V rocket if the scale fac

KengaRu [80]

Answer: 6.4 feet

Step-by-step explanation:

Height of Atlas V rocket = 205 feet

Ratio of the model = 1:32 = 1/32

Model / Real = 1/32

Since Real height = 205, we put it into the equation and this will be:

Model / Real = 1/32

Model / 205 = 1/32

Model × 32 = 205 × 1

Model = 205/32

Model = 6.4 feet

The height of the model is 6.4 feet.

7 0

2 years ago

There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=

yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = $\frac{12P4}{12^{4} }$

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = $\frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }$

P(X=2) = 0.401

P(X=3) = $\frac{4C3 * 12P2}{12^{4} }$

P(x=3) = 0.025

P(X=4) = $\frac{12}{12^{4} }$

P(X=4) = 0.001

Mean, $\mu = \sum xP(x)$

$\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879$

Standard deviation, $SD = \sqrt{\sum x^{2} P(x) - \mu^{2}} \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2} * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}$

SD = 1.033

4 0

3 years ago