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Bad White [126]
3 years ago
10

PLEASE HELP been stuck on this for a while

Mathematics
1 answer:
marysya [2.9K]3 years ago
4 0

Answer:

I believe it's D but I'm not 100 percent sure. I hope this helped I'm sorry I couldn't help more <3

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A researcher wants to study the relationship between salary and gender. She randomly selects 297 individuals and determines thei
padilas [110]

Answer:

The researcher cannot conclude that salary and gender are dependent.

Step-by-step explanation:

A dependent variable is a variable, for example "Salary" that depends on an independent variable, e.g. "Gender."  Salary is the dependent variable while gender is the independent variable.  This means that the value of salary changes in relation to the gender and not vice versa.  Two variables become dependent if they change based on another independent variable that is operating on them.  In this research, the researcher is not trying to measure gender but the relationship between salary and gender.  To achieve her purpose, she shows that salary depends on gender and not that gender depends on salary.

4 0
4 years ago
What is the length of the hypotenuse?
gayaneshka [121]

Answer:

Hello! answer: 5

Step-by-step explanation:

What you do to find the answer for these is do a^2+b^2=c^2 Basically meaning 4 × 4 + 3 × 3 will equal a number that you then find the suare root of square root just meaning a number multiplied by itself to equals that number so...

4 × 4 = 16

3 × 3 = 9

16 + 9 = 25

√25 = 5

5 × 5 = 25 therefore c = 5 hope that helps!

5 0
3 years ago
What is the answer to 1/2+(-2/3)=
iren2701 [21]
<span>1/2+(-2/3)
Multiply until both fractions have the same common denominator
3/6 - 4/6
Subtract the numerator but NOT the denominator
Final Answer: -1/6</span>
6 0
3 years ago
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If I || m, find the value of x (9x-4) ८(5x + 16)
Firdavs [7]
I’m pretty sure it’s x=12
7 0
3 years ago
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Find the inverse of 2∛(x+2)
Artemon [7]
y=2\sqrt[3]{x+2}\ \ \ |divide\ both\ sides\ by\ 2\\\\\sqrt[3]{x+2}=\dfrac{y}{2}\to x+2=\left(\frac{y}{2}\right)^3\ \ \ |subtract\ 2\ from\ both\ sides\\\\x=\dfrac{y^3}{2^3}-2\\\\x=\dfrac{1}{8}y^3-2\\\\\boxed{f(x)=2\sqrt[3]{x+2}\to f^{-1}(x)=\frac{1}{8}y^3-2}
5 0
3 years ago
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