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podryga [215]
3 years ago
14

Which of the following statements are true?

Mathematics
1 answer:
Aneli [31]3 years ago
4 0

Answer: It’s A

Step-by-step explanation:

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The math test has 15 multiple choice questions, each with 3 answers. If Betty guesses correctly on the first 4 questions,
Sonbull [250]

Answer:

90 percent

Step-by-step explanation:

15 divided by 4 so 3.75 i rounded it and i got 4

8 0
3 years ago
Solve the quadratic equation by completing the square x^2+5x-3=0
PIT_PIT [208]

{\tt{x =  \frac{ -b± \sqrt{ {b}^{2} - 4ac } }{2a} }}

{\tt{ x =  \frac{ - 5±\sqrt{{5}^{2}  - 4 \times 1 \times ( - 3)} }{2 \times 1} }}

{\tt{x =  \frac{ - 5±\sqrt{25 + 12} }{2} }}

{\tt{x =  \frac{ - 5 ±\sqrt{37}  }{2} }}

\:  \:

{\tt{x =  \frac{ - 5 +  \sqrt{37} }{2} }}

{\tt{x =  \frac{ - 5 -  \sqrt{37} }{2} }}

8 0
2 years ago
How do you write words to match the expression 24-(6+3)
suter [353]

Twenty-Four minus the quantity Six plus Three

Hope this Helps!!!

3 0
4 years ago
Read 2 more answers
Write an equation in slope-intercept form of the line parallel to y=8x-8 through (5,2)
AlekseyPX

Answer:

The equation would be y = 8x - 38

Step-by-step explanation:

To find the equation of this new line, we first need to identify the slope of the first line. In slope-intercept form, the slope is always the coefficient of x. This makes the slope of the first equation 8. Since parallel lines have the same slope, our new slope will also be 8.

Given that and the point, we can solve for the equation using point-slope form.

y - y1 = m(x - x1)

y - 2 = 8(x - 5)

y - 2 = 8x - 40

y = 8x - 38

3 0
3 years ago
Please help ..............
Naddika [18.5K]
Break the problem into two parts:  1) the area of the this isosceles triangle whose hypotenuse is AB and 2) the area of the semicircle whose diameter is AB.

The triangle is isosceles because the lengths of the two shorter legs are the same (2 meters).  Use the Pythagorean Theorem to find the length of the hypotenuse of this triangle.  (AB)^2 = (2 m)^2 + (2 m)^2, or 8 m^2.  Thus, AB = sqrt(8 m^2), or 2sqrt(2).  This AB is also the base of the triangle.  What is the area of the triangle?

Next, noting that the diameter AB of the semicircle is 2sqrt(2) and the radius is just sqrt(2), find the area of the semicircle.  The area of a circle of radius r
is pi*r^2; here it's pi*(sqrt 2)^2, or pi*2, or 2pi.  

Add the area of the triangle to this area of the semicircle (2pi) to find the total area of the figure.

Hint:  the area of a triangle is (bh)/2, where h is the height, b is the base.
5 0
3 years ago
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