The answer to the question is c. 70°
Answer:

Find the midsegment of the triangle which is parallel to CA.

Tip
- A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
- This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
- If two segments are congruent, then they have the same length or measure.In other words, congruent sides of a triangle have the same length.

We have to find the segment which is parallel to CA.
From the given data,
The segment EG is the midsegment of the triangle
ABC.
So we have,
A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment has two special properties. It is always parallel to the third side.

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Answer:
67
Step-by-step explanation:
Since the diagonals in a rectangle are congruent, AC=BD and
7x+18=10x-3
We need to separate x -- to do that, we can first subtract 7x from both sides, resulting in
18=3x-3
Next, add 3 to both sides to get
21=3x
Divide both sides by 3 to get
x=7
Then, we just plug x into 10x-3 to get BD = 7*10-3 = 67
Answer:
x ≤ 19
Step-by-step explanation:
The instructions here are probably "solve for x." Please include them.
4 - x + 6^2 ≥ 21
becomes 4 - x + 36 ≥ 21
Now combine like terms. 4 and 36 combine to 40: 40 - x ≥ 21, and so:
19 - x ≥ 0
Adding x to both sies results in
x ≤ 19
Please, include the instructions when you post a question. Thanks.