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OleMash [197]
3 years ago
11

A factory makes 1554 units in 14 days with the help of 20 workers. If 2 workers go on leave, how many units can be produced, if

there are only 10 days?​
Mathematics
1 answer:
Firdavs [7]3 years ago
7 0
999 because you do 1554 divided by 14 then divided by 20 to see how much they each make per day which is 5.55 Then do 55.5 times 18 which is 99.9 then times by 10 = 999
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Philip ran out of time while taking a multiple-choice test and plans to guess on the last 4 questions. Each question has 5 possi
belka [17]

Answer:

There is a 40.96% probability that he answers exactly 1 question correctly in the last 4 questions.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either it is correct, or it is not. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which  is the number of different combinatios of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.

In this problem we have that:

There are four questions, so n = 4.

Each question has 5 options, one of which is correct. So

What is the probability that he answers exactly 1 question correctly in the last 4 questions?

This is

There is a 40.96% probability that he answers exactly 1 question correctly in the last 4 questions.

My guess...

⊕⊕⊕

6 0
4 years ago
Bradley completed 3/5 of his homework. What percent of his homework does he still need to complete?
muminat
3/5 = 6/10 (which is 60%) 100% - 60% = 40%
7 0
4 years ago
Read 2 more answers
What is 0.0000001 converted to the tenth power
jenyasd209 [6]

this would look like this: 0.0000001^10

If we were to do 0.0000001*0.0000001 it would be 0.00000000000010

We doubled the zeroes and moved the one up. Continue on until you reach the tenth power.

6 0
3 years ago
Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.† Suppose a small group of 10 Allen's hummingb
ruslelena [56]

Answer: provided in the explanation segment

Step-by-step explanation:

(a). from the question, we can see that since that б is known, we can use standard normal, z.

we are asked to find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error?

⇒ 80% confidence interval for the average weight of Allen's hummingbirds is given thus;

x ± z * б / √m

which is

3.15 ± 1.28 * 0.32/√10

= 3.15 ± 0.1295 = 3.0205 or 3.2795

(b). normal distribution of weight (c) б is known

(c). option (a) and (e) are correct

(d).  from the question, let sample size be given as S

this gives';

1.28 * 0.32/√S = 0.15

√S = (1.28 * 0.32) / 0.15 = 2.73

S = 7.4529

cheers i hope this helps

6 0
3 years ago
Explain how you can use compatible numbers to estimate the whole-number quotient of 925÷29.​
alukav5142 [94]

Answer:

below

Step-by-step explanation:

Round 925 to 900

Round 29 to 30

900/30

= 30

Answer to 925/29:

31.89

7 0
3 years ago
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