Step-by-step explanation:
Suppose a number = A
4(11-A) = 60
(11 - A) = 60/4
11 - A = 15
11 = A + 15
A + 15 = 11
A = 11 - 15
= -4
The area of the <em>irregular</em> quadrilateral ABCD is equal to 234 square centimeters. (Correct choice: C)
<h3>What is the area of the quadrilateral?</h3>
Herein we have a description of an <em>irregular</em> quadrilateral, whose area must be determined by adding the areas of minor quadrilaterals and triangles that are part of it. The area is now determined:
A = 0.5 · (24 cm) · (7 cm) + 0.5 · (15 cm) · (20 cm)
A = 234 cm²
The area of the <em>irregular</em> quadrilateral ABCD is equal to 234 square centimeters. (Correct choice: C)
<h3>Remark</h3>
The picture with the quadrilateral is missing and is included as attachment.
To learn more on quadrilaterals: brainly.com/question/13805601
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3x - 6y = 72...reduce by dividing everything by 3
x - 2y = 24...notice how this is exactly the same as the other equation....means that the lines are the same line...meaning infinite solutions